The question is incomplete. The complete question is :
A dielectric-filled parallel-plate capacitor has plate area A = 10.0 cm2 , plate separation d = 10.0 mm and dielectric constant k = 3.00. The capacitor is connected to a battery that creates a constant voltage V = 15.0 V . Throughout the problem, use ϵ0 = 8.85×10−12 C2/N⋅m2 .
Find the energy U1 of the dielectric-filled capacitor. I got U1=2.99*10^-10 J which I know is correct. Now I need these:
1. The dielectric plate is now slowly pulled out of the capacitor, which remains connected to the battery. Find the energy U2 of the capacitor at the moment when the capacitor is half-filled with the dielectric.
2. The capacitor is now disconnected from the battery, and the dielectric plate is slowly removed the rest of the way out of the capacitor. Find the new energy of the capacitor, U3.
Solution :
Given :
d = 10 mm
= 0.010 m
Then, Capacitance,
Now,
And
In parallel combination,
Then energy,
b). Now the charge on the is :
Now when the capacitor gets disconnected from battery and the is slowly of the way out of the is :
Without the dielectric,
Answer:Technician A
Explanation:
Technician A is right as a 12 v battery contains 6 cells of 2.2 volts and
The size of the battery plates and amount of electrolyte decides the amount of charge lead acid batteries can store for example thus more plates a cell does not mean more voltage it creates.
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Explanation:
Answer:
The density of the sun is 4434kg/m³
This was found by dividing the mass (1.989 ×10³⁰kg) by the volume (4.486×10²⁶ m³) which was calculated using V = 4/3×pi ×r³
Explanation:
See attachment below.
What does Michaelis believe caused Myrtle to run? He thinks she was running away from Wilson. She thought Tom was in the yellow car because she had seen him in it earlier. She was running towards Tom