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kompoz [17]
4 years ago
5

EXPLAIN HOW ENERGY IS TRANSMITTED THROUGH A MEDIUM

Physics
2 answers:
Alex777 [14]4 years ago
7 0
Energy can be transmitted through a medium in one of 3 ways:

Conduction -  This occurs when particles of a substance collide with one another, transferring some of their energy to each other in the process. This generally occurs most rapidly in solids due to the close proximity and order of the particles, and most slowly in gases, due to the sparse nature of the particles.

Convection - This occurs when a fluid has a temperature gradient decreasing with increasing altitude. For example, when a pan of water is heated, the higher energy water molecules at the bottom have a lower density than the lower energy molecules at the top of the pan and travel upwards through the liquid, while their place is taken by the lower energy molecules. This phenomenon also occurs in gases (think hot air balloon).

Radiation - This does not involve the movement of particles whatsoever, instead the energy is being transferred in the form of electromagnetic radiation (such as light). This is how the Sun heats the earth, as there are very few particles in space, certainly not enough for conduction/convection. (Note: this does technically involve the movement of particle called photons that make up the radiation, but they are not treated as physical particles like molecules).

Hope this helps.
jek_recluse [69]4 years ago
5 0
I say it helped then because TrueType had room
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-- gravity, directed downward
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These two forces must be exactly equal, so that the net
vertical force on the raft is zero.  Otherwise, it would be
accelerating either up or down.

Horizontal forces:
We know that the net horizontal force on the raft is zero. 
Otherwise, it would be accelerating horizontally.

But we don't know if there are actually no horizontal forces
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3 0
3 years ago
Use the information below to answer questions
Ulleksa [173]

Answer:

The charges are q₁  = 2 × 10⁻⁸ C and  q₂ = 3 × 10⁻⁸ C

Explanation:

Here is the complete question

Two identical tiny balls have charge q1 and q2. The repulsive force one exerts on the other when they are 20cm apart is 1.35 X 10-4 N. after the balls are touched together and then represented once again to 20cm, now the repulsive force is found to be 1.40 X 10-4 N. find the charges q1 and q2.

Solution

The force F = 1.35 × 10⁻⁴ N when the charges are separated a distance of r = 20 cm = 0.2 m is given by

F = kq₁q₂/r₁²

q₁q₂ = Fr₁²/k

q₁q₂ = 1.35 × 10⁻⁴ N × (0.2 m)²/9 × 10⁹ Nm²/C² = 0.054/9 × 10⁻¹³ C² = 0.006 × 10⁻¹³ C² = 6 × 10⁻¹⁶ C²

q₁q₂ = 6 × 10⁻¹⁶ C² (1)

When the charges are brought together, the charge is now q = (q₁ + q₂)/2

The new repulsive force F = 1.406 × 10⁻⁴ N  at a distance of r₂ = 20 cm = 0.2 m is then

F₂ = kq²/r₂²

q² = F₂r₂²/k = 1.406 × 10⁻⁴ N × (0.2 m)²/9 × 10⁹ Nm²/C² = 0.00625 × 10⁻¹³ C² = 6.25 × 10⁻¹⁶ C²

q² = 6.25 × 10⁻¹⁶ C²

q = √(6.25 × 10⁻¹⁶) C

q = 2.5 × 10⁻⁸ C

(q₁ + q₂)/2 =  2.5 × 10⁻⁸ C

(q₁ + q₂) = 2 × 2.5 × 10⁻⁸ C

q₁ + q₂ = 5 × 10⁻⁸ C (2)

q₁  = 5 × 10⁻⁸ C - q₂  (3)

Substituting equation (3) into (1), we have

(5 × 10⁻⁸ C - q₂)q₂ = 6 × 10⁻¹⁶ C²

Expanding the bracket, we have

(5 × 10⁻⁸ C)q₂ - q₂² = 6 × 10⁻¹⁶ C²

So, q₂² - (5 × 10⁻⁸ C)q₂ + 6 × 10⁻¹⁶ C² = 0

Using the quadratic formula to find q₂

q_{2} = \frac{-(-5 X 10^{-8} )+/- \sqrt{(-5 X 10^{-8} )^{2} - 4X1X6 X 10^{-16} } }{2X1}\\  = \frac{5 X 10^{-8} )+/- \sqrt{25 X 10^{-16}  - 24 X 10^{-16} } }{2}\\= \frac{5 X 10^{-8} )+/- \sqrt{1 X 10^{-16} } }{2}\\= \frac{5 X 10^{-8} )+/- 1 X 10^{-8} }{2}\\= \frac{5 X 10^{-8} + 1 X 10^{-8} }{2} or \frac{5 X 10^{-8}  - 1 X 10^{-8} }{2}\\= \frac{6 X 10^{-8} }{2} or \frac{4 X 10^{-8}}{2}\\= 3 X 10^{-8} C or 2 X 10^{-8} C

q₁  = 5 × 10⁻⁸ C - q₂

q₁  = 5 × 10⁻⁸ C - 3 × 10⁻⁸ C or 5 × 10⁻⁸ C - 2 × 10⁻⁸ C

q₁  = 2 × 10⁻⁸ C or 3 × 10⁻⁸ C

So the charges are q₁  = 2 × 10⁻⁸ C and  q₂ = 3 × 10⁻⁸ C

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If youre walking from point a to b, the magnitude of your displacement will always be equal or less than or greater than your di
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The magnitude of your displacement can be equal to the distance you covered, or it can be less than the distance you covered.  But it can never be greater than the distance you covered.

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The straight line is always the shortest path between two points.

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If a ball is thrown horizontally with a speed of 65 mph, how far will it fall while traveling 90 ft of horizontal distance?
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Answer:

install socrati it give you all answers

Explanation:

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Which are ways to improve the design of this experiment? Check all that apply.
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