Answer:
Order, sensitivity or response to the environment, reproduction, growth and development, regulation, homeostasis, and energy processing.
The <span>simple machine found on the head of the ax is </span>Wedge. A wedge is an inclined plane that can be moved. When an ax is used
to split wood, the ax handle
exerts a force on the blade of
the axe, which is the wedge. That force pushes the wedge
down into the wood. The wedge in turn exerts an
output force splitting the wood in two.
The volume of 15.7 M H2SO4 is required to prepare 12.0 L of 0.156 M sulfuric acid is 0.12 L
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Molarity of stock solution (M₁) = 15.7 M
- Volume of diluted solution (V₂) = 12 L
- Molarity of diluted solution (M₂) = 0.156 M
- Volume of stock solution needed (V₁) = ?
<h3>How to determine the volume of the stock solution needed</h3>
The volume of the stock solution needed can be obtained by using the dilution formula as shown below:
M₁V₁ = M₂V₂
15.7 × V₁ = 0.156 × 12
15.7 × V₁ = 1.872
Divide both side by 15.7
V₁ = 1.872 / 15.7
V₁ = 0.12 L
Thus, the volume of the stock solution needed to prepare the solution is 0.12 L
Learn more about dilution:
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Answer:
a. 916.95K is final temperature of the gas
b. 3667.8K
Explanation:
a. We can solve the temperature of a gas when the volume is expanded three times using Gay-Lussac's law:
P₁T₂ = P₂T₁
<em>Where P is pressure,</em>
<em>And T is absolute temperature of 1, initial states and 2, final states of the gas.</em>
<em />
Initial pressure is 6.60 atm, initial absolute temperature is 32.5°C + 273.15K = 305.65K. Final pressure is three times initial pressure = 6.60atm*3 = 19.8atm.
Solving for final temperature:
P₁T₂ = P₂T₁
6.60atm*T₂ = 19.8atm*305.65K
T₂ =
916.95K is final temperature of the gas
<em />
b. Charle's law is the gas law that relates changes in volume and temperature of a gas:
V₁T₂ = V₂*T₁
If the volume is quadrupled: V₂/V₁ = 4:
T₂ = 4*916.95K
T₂ = 3667.8K
The vapor pressure of the two jars are the same.
The volume of water inside the container does not change the vapor pressure.
As long as the liquid remains being water and the temperature does not change the vapor pressure will be the same. The vapor pressure depends only in the nature of the substance and the temperature of the system.
If you want to know more about this, i.e. why, here you have additional explanation:
The vapor pressure is the pressure of the vapor of a substance in equilibrium with the substance in liquid (or solid state) and it is due to the fact that some molecules in the liquid (or solid), those that are close to the surface of liquid in contact with the gas phase and that have enough kinetic energy, evaporate.
At equilibrium the number of molecules passing from the liquid state to the gas state is equal to the number of molecules that pass from the gas state to the liquid state. If the volume of liquid is increased or decreased, as long as the temperaature of the system remains constant the equilibrium is reached again with the same vapor pressure.