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Marianna [84]
3 years ago
12

How are mass and weight alike?

Chemistry
1 answer:
joja [24]3 years ago
7 0
Both mass and weight are measured by using scales.
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Animals communicate for various reasons, but one main reason is for reproduction. In what ways do animals communicate with other
Natasha_Volkova [10]

Animals communicate using signals, which can include visual; auditory, or sound-based; chemical, involving pheromones; or tactile, touch-based, cues

6 0
2 years ago
What’s the difference between attractive forces and covalent bonds
Scrat [10]

Answer:

<em>An intramolecular force is between that atoms makeup a molecule. An intermolecular force is between entire molecules. A non-polar covalent bond occurs when the electrons are equally shared between atoms.</em>

3 0
3 years ago
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A weak base. B. has a K. of 4.46 x 10-10 A solution with an unknown initial concentration is tested, and found to have a pH of 8
Ann [662]

Answer:

0.013MB

Explanation:

6 0
3 years ago
Balance the following redox reaction by inserting the appropriate coefficients. SO4^2- + NH3 = SO3^2- + H2O + N2
Harlamova29_29 [7]

SO₄²⁻  +NH₃  →   SO₃²⁻ + H₂O  +N₂

The  balanced  of  the above  redox reaction   is as below

3SO₄²⁻ + 2NH₃   →  3SO₃²⁻  + 3 H₂O  + N₂


 Explanation

According   to the law of mass conservation the  number  of atoms  in the reactant side  must  be equal to number of atoms in product side.

Inserting coefficient 3 in front of SO₄² , 2  in front  of NH₃, 3 in front  of SO₃²⁻  and 3 in front  of H₂O balance the equation above. This  is  because  the number  of atoms  are equal in both side.

for example there are 2 atoms of N in both side of the reaction.

6 0
3 years ago
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A gas sample with a volume of 1,500 cm® is heated from -65 °C to 75 °C. Assuming the
djverab [1.8K]

Answer:

V₂ = 2509.62 cm³

Explanation:

Given data:

Initial volume = 1500 cm³

Initial temperature = -65°C (-65 + 273 = 208 K)

Final temperature = 75°C ( 75 +273 = 348 K)

Final volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 1500 cm³ × 348 K / 208 k

V₂ = 522000 cm³.K / 208 k

V₂ = 2509.62 cm³

7 0
3 years ago
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