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Daniel [21]
3 years ago
13

A solution of HCl has H+ = 0.01 M. What is the pH of this solution?–2, –1 ,1 ,2

Chemistry
2 answers:
aleksley [76]3 years ago
5 0

Answer:

2

Explanation:

pH= -log[H+]

[H+]= 0.01M or 1×10^-2M

pH= -log(1×10^-2)

pH= 2

Step2247 [10]3 years ago
4 0
PH = -log[H⁺]
pH = -log[0,01]
<u>pH = 2
</u>
_____________
:)
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Use molecular structure and intermolecular bonding to describe why bromine has a lower boiling point than water
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Answer:

Bromine mollecules are held together by van der waals forces while a water molecule constitutes both van der waals forces and hydrogen bomnding

Explanation:

This makes the water molecule recquire more heat energy to break the bond thus a higher boiling point while bromine structure requires just litttle heat energy  

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If Santa Claus is in the beach then what will you call him?​
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Which ones react with water?
slavikrds [6]

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8 0
2 years ago
a solution of KCl in water has a concentration of 0.243 M. The solution has a volume of 0.580 L. How many grams of KCl are prese
Novosadov [1.4K]

Answer:

10.5 g

Explanation:

Step 1: Given data

  • Molar concentration of the solution (C): 0.243 M
  • Volume of solution (V): 0.580 L

Step 2: Calculate the moles of solute (n)

Molarity is equal to the moles of solute divided by the liters of solution.

M = n/V

n = M × V

n = 0.243 mol/L × 0.580 L = 0.141 mol

Step 3: Calculate the mass corresponding to 0.141 moles of KCl

The molar mass of KCl is 74.55 g/mol.

0.141 mol × 74.55 g/mol = 10.5 g

8 0
3 years ago
0.32 g of a walnut is burned under an aluminum can filled with 58.1 mL of water. The water temperature in the can increases by 3
balu736 [363]

Answer:

1.8 × 10² cal

Explanation:

When 0.32 g of a walnut is burned, the heat released is absorbed by water and used to raise its temperature. We can calculate this heat (Q) using the following expression.

Q = c × m × ΔT

where,

c: specific heat capacity of water

m: mass of water

ΔT: change in the temperature

Considering the density of water is 1 g/mL, 58.1 mL = 58.1 g.

Q = c × m × ΔT

Q = (1 cal/g.°C) × 58.1 g × 3.1°C

Q = 1.8 × 10² cal

3 0
3 years ago
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