Answer:
22.95g
Explanation:
Given parameters:
Percentage by mass of silver in silver iodide = 45.9%
Mass of silver iodide given = 50g
Unknown:
Mass of silver in silver iodide = ?
Solution:
The formula of the compound is;
Silver iodide = AgI
Since the percentage by mass of silver in the compound is 45.9%;
Mass of silver = percentage by mass of silver x mass of AgI
Mass of silver = 
x 50 = 22.95g
We are given with
<span>ΔHo = 38.0 kJ
ΔSo = 112.9
for these standard conditions:
To = 25 C
Po = 1 atm
Using the Clapeyron Equation
ln (P/Po) = (</span><span>ΔHo / R)(1/T1 - 1/T2)
Substitute the values and solve for P (Temperature should be in Kelvin)</span>
Answer:
CaO + SO 3 → CaSO. 4
This is an acid-base reaction (neutralization): CaO is a base, SO 3 is an acid.
<span>moles glucose = 19 g / 180 g/mol= 0.105
M = 0.105 / 0.100 L = 1.05
moles in 20.0 mL = 1.05 M x 0.0200 L = 0.0216
New concentration = 0.0216 /0.500 L = 0.0432 M
moles in 100 mL = 0.100 L x 0.0432 = 0.00432
mass = 0.00432 x 180 g/mol= 0.778 g</span>
