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DochEvi [55]
3 years ago
15

Redox reactions can be written as two half-reactions, focusing on the gain or loss of electrons by one of the chemical substance

s. One half-reaction shows the oxidation while the other shows the reduction. When the two half-reactions are combined, the overall reaction is obtained.The half-reactions can aid in the balancing of redox equations because the number of each element must be balanced as well as the number of electrons gained and lost. What substance is added to balance the hydrogen in a half-reaction?
A. H₂O₂
B. H₂O
C. H⁺
D. H₂
Chemistry
1 answer:
lutik1710 [3]3 years ago
5 0

Answer:

C) H⁺

Explanation:

When we are balancing the reaction<em> in an acid medium</em>, hydrogen is balanced using the <u>H⁺</u> species. This is most likely the intended answer of your question.

When the reaction takes place not in an acid medium, but in <em>an alkaline one</em>, then hydrogen is present as the OH⁻ species. However this option is not given in your question.

Thus the answer is option C).

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What type of soils are more likely to transmit contaminants
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Chemicals can attach more easily to soils with a higher content of clay and organic matter. In addition, sandy soils generally do not contain a large amount of soil organisms compared with other soil types.

Explanation:

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2 years ago
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The Brazos River is a major river in Texas. In many parts of the Cross Timbers and Prairies ecoregion, the river has formed tall
musickatia [10]

Answer:

Weather and erosion.

Explanation:

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8 0
2 years ago
A sodium atom has a mass number of 23. Its atomic number is 11. How many electrons does a neutral sodium atom have?
NemiM [27]

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Explanation:

4 0
3 years ago
What is the molarity of a solution containing 23 g of NaCl in 500 mL of solution?
trapecia [35]

molarity of a solution means mols per liter.

First, you need to convert 23 grams on NaCl into mols. 23g divided by molar mass (58.44g/mol) which gives you .394 mols.

Now, you need to convert 500ml to L which moves the decimal three places to the left, giving you .500L of solution.

Finally, divide the mols over solution to get .787M

7 0
2 years ago
A 2.026g sample of a hydrate of sodium carbonate (Na2CO3) is heated to remove water. After heating, the mass of the sample is 0.
OLEGan [10]

Answer:

62.98 % of the sample of hydrate is water

Explanation:

Step 1: Data given

Mass of the sample of a hydrate of sodium carbonate (Na2CO3) = 2.026 grams

After heating, the mass of the sample is 0.750 g

Molar mass H2O = 18.02 g/mol

Step 2: Calculate mass of water

Mass water = mass of hydrate - mass of sample after heating

Mass water = 2.026 grams - 0.750 grams

Mass water = 1.276 grams

Step 3: Calculate mass % percent of water

Mass % of water = (mass of water / total mass hydrate) * 100 %

Mass % of water = (1.276 grams / 2.026 grams) *100 %

Mass % of water = 62.98 %

62.98 % of the sample of hydrate is water

7 0
3 years ago
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