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juin [17]
3 years ago
13

Which change is exothermic?

Chemistry
1 answer:
Lina20 [59]3 years ago
6 0
The answer is (1) freezing of water. The energy of different status is increase from solid to liquid to gas. So the change of liquid to solid is exothermic. The other three are endothermic.
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As noted in Assignment 1.4.1., alkylation of benzene with 1-chlorobutane in the presence of AlCl3 gives both butylbenzene and (1
Sunny_sXe [5.5K]

Answer:

Use the Bromotriflouride catalyst, BF₃

Explanation:

The BF₃ is most likely to yield less desired side products. The effect lies in the reaction mechanism.

BF₃ is a Lewis acid. Its role is to promote the ionization of the HF. This is achieved through the electrophilic mechanism. The reaction mechanism is as follows:

2 - methylpropene + H-F-BF₃ → H-F + H₃C + benzene

butylbenzene + F-BF₃ → tert-butylbenzene + H-F + BF₃ (regenerated catalyst)

6 0
3 years ago
What is the difference between a contractor and a starter
Lunna [17]
"A contactor is a electrically controlled switch which uses an electromagnetic coil to pull in the contacts.”

"A motor starter is a contactor, plus an overload relay that will drop out the coil voltage if the motor overloads. If there is not overload relay, it is not a starter any longer, it's back to being just a contactor."
6 0
4 years ago
using the above equation, how many moles of sulfur can be produced if 0.5640 moles of sulfur dioxide are used with excess hydrog
Step2247 [10]

Answer:

  • <u><em>1.692 mol of sulfur</em></u>

Explanation:

<u>1. Write the balanced chemical equation</u>

       2H₂S + SO₂ → 2H₂O + 3S

<u>2. State the mole ratio</u>

   1molSO_2:3molS

<u>3. Calculate the moles of S</u>

  • Moles S = 0.5640 mol SO₂  × (3 mol S / 1 mol SO₂) = 1.692 mol S
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3 years ago
A certain compound is made up of one phosphorus (p) atom, three chlorine (cl) atoms, and one oxygen (o) atom. what is the chemic
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8 0
4 years ago
According to Graham’s law, the rate of effusion of a gas is inversely proportional to
VLD [36.1K]

C.  the square root of the mass of the particles.

<h3>Further explanation  </h3>

Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or  

the effusion rates of two gases = the square root of the inverse of their molar masses:  

\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

or  

\rm M_1\times r_1^2=M_2\times r_2^2

From this equation shows that the greater the mass of the gas, the smaller the effusion rate of the gas and vice versa, the smaller the mass of the gas, the greater the effusion velocity.

So if both gases are at the same temperature and pressure, the above formula can apply

5 0
3 years ago
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