Answer:
7.12 mm
Explanation:
From coulomb's law,
F = kqq'/r².................... Equation 1
Where F = force, k = proportionality constant, q and q' = The two point charges, r = distance between the two charges.
Make r the subject of the equation,
r = √(kqq'/F).......................... Equation 2
Given: q = q' = 75.0 nC = 75×10⁻⁹ C, F = 1.00 N
Constant: k = 9.0×10⁹ Nm²/C².
Substitute into equation 2
r = √[ (75×10⁻⁹ )²9.0×10⁹/1]
r = 75×10⁻⁹.√(9.0×10⁹)
r = (75×10⁻⁹)(9.49×10⁴)
r = 711.75×10⁻⁵
r = 7.12×10⁻³ m
r = 7.12 mm
Hence the distance between the point charge = 7.12 mm
Answer:
820.864 g
Explanation:
1) The atomic mass of sulfur (found from the periodic table) is 32.065 amu. Use this mass to find the molar mass of Sulfur. Sulfur is S8 so the molar mass of sulfur is:
8 × 32.065 = 256.52 g/mol
2) To find the mass use the formula:
m = n × M where <em>m</em><em> </em>is the mass, <em>n</em><em> </em>is the number of moles, and <em>M</em><em> </em>is the molar mass.
3)
Answer:
The wood
Explanation:
The block of wood shall float in the water while the iron key would sink due to the weight.
Answer:
Nonetheless, scientific change is connected with many other key issues in philosophy of science and broader epistemology, such as realism, rationality and relativism. The present article does not attempt to address them all. Higher-order debates regarding the methods of historiography or the epistemology of science, or the disciplinary differences between History and Philosophy, while important and interesting, represent an iteration of reflection on top of scientific change itself, and so go beyond the article’s scope.
Explanation:
Answer:
4 g after 58.2 years
0.0156 After 291 years
Explanation:
Given data:
Half-life of strontium-90 = 29.1 years
Initially present: 16g
mass present after 58.2 years =?
Mass present after 291 years =?
Solution:
Formula:
how much mass remains =1/ 2n (original mass) ……… (1)
Where “n” is the number of half lives
to find n
For 58.2 years
n = 58.2 years /29.1 years
n= 2
or 291 years
n = 291 years /29.1 years
n= 10
Put values in equation (1)
Mass after 58.2 years
mass remains =1/ 22 (16g)
mass remains =1/ 4 (16g)
mass remains = 4g
Mass after 58.2 years
mass remains =1/ 210 (16g)
mass remains =1/ 1024 (16g)
mass remains = 0.0156g
