Answer:
Reflection of Light. When light waves are incident on a smooth, flat surface, they reflect away from the surface at the same angle as they arrive. ... Regardless of whether light is acting as particles or waves, however, the result of reflection is the same.
Answer:
5kgm
Explanation:
convert cm to m and g to kg
250/1000=0.25kg
5/1000=0.05m
then find the density
density=mass/volume
=0.25kg/0.05m
=5kgm
Answer:
The fluids speed at a) 
and b) 
are 
and 
respectively
c) Th volume of water the pipe discharges is: 
Explanation:
To solve a) and b) we should use flow continuity for ideal fluids:
(1)
With Q the flux of water, but Q is 
using this on (1) we have:
(2)
With A the cross sectional areas and v the velocities of the fluid.
a) Here, we use that point 2 has a cross-sectional area equal to 
, so now we can solve (2) for 
:
b) Here we use point 2 as 
:
c) Here we need to know that in this case the flow is the volume of water that passes a cross-sectional area per unit time, this is 
, so we can write:
, solving for V:
Answer:
F = - 2 A x - B
Explanation:
The force and potential energy are related by the expression
F = - dU / dx i ^ -dU / dy j ^ - dU / dz k ^
Where i ^, j ^, k ^ are the unit vectors on the x and z axis
The potential they give us is
U (x) = A x² + B x + C
Let's calculate the derivatives
dU / dx = A 2x + B + 0
The other derivatives are zero because the potential does not depend on these variables.
Let's calculate the strength
F = - 2 A x - B
Answer: 219,344.5 j
Explanation:
from the question we have the following parameters
mass of barge (m) = 5 x 10^4 kg
angle of ropes (θ) = 45 degrees
force by each mule (F1) = 1.10 kN = 1100 N
force by each mule (F2) = 1.10 kN = 1100 N
distance (s) = 141 m
work done by the mules = force x cos θ x distance
since we are calculating the force of both mules we have to both mules before we can use in the equation
force = 1100 + 1100 = 2200 N
work done = 2200 x cos (45) x 141
work done = 219,344.5 j
