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3 years ago

ILL GIVE BRAINLY THING

Physics

1 answer:

Bogdan [553]3 years ago

4 0

Answer:

About 3 trips

Explanation: if we do 2.5m*1.6m*0.75 it equals to 11000 then we divide that to 11m3 and it gives you 3.6 so it will be about 3 times

Thx

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A car moves at 45 kilometers per hour.

AnnyKZ [126]

Answer:

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3 years ago

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The gravitational force of attraction be-

Sliva [168]

Answer:

2.15 m

Explanation:

Newton's Law of Universal Gravitation:

$\displaystyle F_g = G \frac{m_1 m_2}{r^2}$

$\displaystyle F_g$ is the gravitational force of attraction

$\displaystyle G$ is the universal gravitational constant

$m_1$ and $m_2$ are the two masses of the two objects

$\displaystyle r$ is the distance between the centers of the two objects.

List the known values:

$\displaystyle F_g = 3.47 \cdot 10^-^8 \ \text{N}$
$\displaystyle G = 6.673 \cdot 10^-^1^1 \ \frac{Nm^2}{kg^2}$
$\displaystyle m_1 = 44.8 \ \text{kg} \\ m_2 = 53.9 \ \text{kg}$
$\displaystyle r =\ ?$

Plug these values into the equation:

$\displaystyle 3.47 \cdot 10^-^8 \ \text{N} = 6.673 \cdot 10^-^1^1 \ \frac{Nm^2}{kg^2} \frac{(44.8 \ \text{kg})(53.9 \ \text{kg})}{r^2}$

Notice that the units $\displaystyle \text{N}$ , $\displaystyle \text{kg}^2$ , and $\displaystyle \text{m}$ cancel out. We are left with the unit $\displaystyle \text{m}$ for radius r.

Get rid of the units to make the problem easier to read.

$\displaystyle 3.47 \cdot 10^-^8= 6.673 \cdot 10^-^1^1 \ \frac{(44.8)(53.9) \ }{r^2}$

Multiply the masses together.

$\displaystyle 3.47 \cdot 10^-^8= 6.673 \cdot 10^-^1^1 \ \frac{(2414.72)}{r^2}$

Multiply the gravitational constant and the masses together.

$\displaystyle 3.47 \cdot 10^-^8= \frac{1.61134265\cdot 10^-^7}{r^2}$

Solve for $r^2$ by dividing both sides by 3.47 * 10^(-8) and moving $r^2$ to the left.

$\displaystyle r^2 = \frac{1.61134265\cdot 10^-^7}{3.47\cdot 10^-^8}$
$r^2 = 4.64363876$

Take the square root of both sides.

$r=2.154910383$

The students are sitting about 2.15 m apart from each other.

4 0

3 years ago

What is the acceleration due to gravity of an object with a mass of 10000 g?

Aleks [24]

The acceleration due to gravity of an object with a mass of 10000 g = 42.02 x 10^-16 m/s²

<h3>What is gravitational constant?</h3>

According to Sir Isaac Newton's rule of universal gravitation and Albert Einstein's theory of general relativity, the gravitational constant, indicated by the capital G, is an empirical physical constant that is used to calculate the gravitational effects.

<h3>According to the given information:</h3>

mass of object = 10kg

gravitational constant = 6.67 x 10^-11

radius of earth = 6.3 x 10^6

we know that:

acceleration due to gravity = GM/R²

= ((6.67 x 10^-11)*10)/(6.3 x 10)²

Solving this we get :

42.02 x 10^-16 m/s²

The acceleration due to gravity of an object with a mass of 10000 g = 42.02 x 10^-16 m/s²

To know more about acceleration due to gravity visit:

brainly.com/question/13860566

#SPJ4

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