Answer:
r = 0m is the Minimum distance from the axis at which the block can remain in place wothout skidding.
Explanation:
From a sum of forces:
where Ff = μ * N and
N - m*g = 0 So, N = m*g. Replacing everything on the original equation:
(eq2)
Solving for r:
If we analyze eq2 you can conclude that as r grows, the friction has to grow (assuming that ω is constant), so the smallest distance would be 0 and the greatest 1.41m. Beyond that distance, μ has to be greater than 0.83.
Answer:
Explanation:
<u>Sum of Vectors in the Plane</u>
Given two vectors
They can be expressed in their rectangular components as
The sum of both vectors can be done by adding individually its components
If the vectors are given as a magnitude and an angle , each component can be found as
The first vector has a magnitude of 3.14 m and an angle of 30°, so
The second vector has a magnitude of 2.71 m and an angle of -60°, so
The sum of the vectors is
Finally, we compute the magnitude of the sum
The rate of acceleration is
Explanation:
Since the ball is moving at constant acceleration, we can solve the problem by using the following suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacement
For the ball in this problem,
u = 0
v = 5.00 m/s
s = 19.6 m
Solving for a, we find the acceleration:
Learn more about acceleration:
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