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miskamm [114]
3 years ago
13

What aspect of speech sound is the primary factor in determining if one perceives the /ba/ sound or the /pa/ sound?

Physics
1 answer:
nignag [31]3 years ago
3 0
The answer is voice onset time. It is a part of the production of stop consonants. Its definition is the length of time that passes between the release of a stop consonant and the start of the voicing and the vibration of the vocal folds.
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A bike travels at 20mph for 5 hours, then 10 mph for 3 hours. What is the average speed?
d1i1m1o1n [39]

Answer:

10 mph

Explanation:

5 0
3 years ago
A small rock is thrown vertically upward with a speed of 17.0m/s from the edge of the roof of a 26.0m tall building. The rock do
Pachacha [2.7K]

Answer:

A) v = 28.3 m/s

B) t =  4.64 s

Explanation:

A)

  • Assuming no other forces acting on the rock, since the accelerarion due to gravity close to the surface to the Earth can be taken as constant, we can use one of the kinematic equations in order to get first the maximum height (over the roof level) that the ball reaches:

        v_{f}^{2} - v_{o}^{2} = 2* g* \Delta h  (1)

  • Taking into account that at this point, the speed of the rock is just zero, this means vf=0 in (1), so replacing by the givens and solving for Δh, we get:

       \Delta h = \frac{-v_{o} ^{2}}{2*g} = \frac{-(17.0m/s)^{2} }{2*(-9.8m/s2)} = 14.8 m (2)

  • So, we can use now the same equation, taking into account that the initial speed is zero (when it starts falling from the maximum height) and that the total vertical displacement is the distance between the roof level and the ground (26.0 m) plus the maximum height that we have just found in (2) , 14.8m:
  • Δh = 26.0 m + 14. 8 m = 40.8 m (3)
  • Replacing now in (1), we can solve for vf, as follows:

       v_{f} =\sqrt{2*g*\Delta h} = \sqrt{2*9.8m/s2*40.8m} = 28.3 m/s (4)

B)

  • In order to find the total elapsed from when the rock is thrown until it hits the street, we can divide this time in two parts:
  • 1) Time elapsed from the the rock is thrown, until it reaches to its maximum height, when vf =0
  • 2) Time elapsed from this point until it hits the street, with vo=0.
  • For the first part, we can simply use the definition of acceleration (g in this case), making vf =0, as follows:

       v_{f} = v_{o} + a*\Delta t = v_{o} - g*\Delta t = 0 (5)

  • Replacing by the givens in (5) and solving for Δt, we get:

       \Delta t = \frac{v_{o}}{g} = \frac{17.0m/s}{9.8m/s2} = 1.74 s (6)

  • For the second part, since we know the total vertical displacement from (3), and that vo = 0 since it starts to fall, we can use the kinematic equation for displacement, as follows:

       \Delta h = \frac{1}{2} * g * t^{2}  (7)

  • Replacing by the givens and solving for t in (7), we get:

       t_{fall} =\sqrt{\frac{2*\Delta h}{g}} = \sqrt{\frac{2*40.8m}{9.8m/s2} } = 2.9 s (8)

  • So, total time is just the sum of (6) and (8):
  • t = 2.9 s + 1.74 s = 4.64 s
5 0
3 years ago
A piece of aluminum has a volume of 4.89 x 10-3 m3. The coefficient of volume expansion for aluminum is = 69 x 10-6(C°)-1. The t
Leno4ka [110]

Answer:

11.515 Joule

Explanation:

Volume of aluminium = V = 4.89×10⁻³ m³

Coefficient of volume expansion for aluminum = α = 69×10⁻⁶ /°C

Initial temperature = 19.1°C

Final temperature = 357°C

Pressure of air = 1.01×10⁵ Pa

Change in temperature = ΔT= 357-19.1 = 337.9 °C

Change in volume

ΔV = αVΔT

⇒ΔV = 69×10⁻⁶×4.89×10⁻³×337.9

⇒ΔV = 114010.839×10⁻⁹ m³

Work done

W = PΔV

⇒W = 1.01×10⁵×114010.839×10⁻⁹

⇒W = 11.515 J

∴ Work is done by the expanding aluminum is 11.515 Joule

7 0
3 years ago
What is the wavelength of a wave that has a speed of 3 km/s and a frequency of 12 Hz? A. 36 km B. 3.6 km C. 0.25 km D. 4 km
butalik [34]

Answer:

c. 0.25km

Explanation:

v=f x wavelength

3000 = 12 x wavelength

wavelength = 3000/12 = 250m

250m to km

To convert m to km, we divide by 1000

250/1000 =0.25km

wavelength = 0.25km

3 0
3 years ago
Las carreras de velocidad pura en el atletismo son:
zheka24 [161]
La respuesta es la letra b
8 0
3 years ago
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