How do i solve seventh degree polynomials

What is the value of x to the nearest tenth

natima [27]

11.1901810337

I think

3 0

3 years ago

Sleep deprivation, CA vs. OR, Part I. According to a report on sleep deprivation by the Centers for Disease Control and Preventi

vlabodo [156]

Answer:

0.008±0.0095=(-0.0015,0.0175)

Step-by-step explanation:

In this case we must use the formula to calculate the confidence interval for the difference between two proportions given by inferential statistics. The formula to calculate both limits of the interval is as it follows:

$(p_{1}-p_{2} )+\sqrt[]{\frac{p_{1}(1-p_{1})}{n_{1} }+\frac{p_{2}(1-p_{2})}{n_{2}} } \\(p_{1}-p_{2} )-\sqrt[]{\frac{p_{1}(1-p_{1})}{n_{1} }+\frac{p_{2}(1-p_{2})}{n_{2}} }$

Where:

$p_{1}$ : proportion of population one (in our case: Oregon residents who reported insufficient rest or sleep)

$p_{2}$ : proportion of population two (in our case: California residents who reported insufficient rest or sleep)

$z_{(∝/2)}$ : quantile of the normal distribution with α/2 probability (in our case, from the standard normal table we have 1.96 for a confidence level of 95%)

$n_{1}$ : sample size for population one (in our case, sample of Oregon residents)

$n_{2}$ : sample size for population two (in our case, sample of California residents)

Now, with our data we have:

$p_{1}$ =0.088

$p_{2}$ =0.08

$z_{(∝/2)}$ =1.96

$n_{1}$ =4,691

$n_{2}$ =11,545

Therefore, we obtain:

$(0.088-0.08)+1.96\sqrt{\frac{0.088(1-0.088)}{4,691}+\frac{0.08(1-0.08)}{11,545} } \\(0.088-0.08)-1.96\sqrt{\frac{0.088(1-0.088)}{4,691}+\frac{0.08(1-0.08)}{11,545} }$

Finally, the result for our interval:

0.008+0.0095=(-0.0015,0.0175)

According to the result we can say with a 95% confidence, that the proportion of Oregon residents with sleep deprivation issues is the same as the proportion of California residents. The reason for this is that 0 (zero) is contained within the interval.

7 0

3 years ago

Please help, show work! Limits and functions! 85 points!

swat32

Answer:

Ok I might misunderstand this but this is what I got ( in order )