Carbon-14 is a naturally occurring carbon isotope.
Carbon-14 has a known half-life.
Carbon-14 is present in all living organisms.
Consider the motion towards right as positive and motion towards left as negative.
m₁ = mass of the cart moving to right = 0.500 kg
v₁ = initial velocity before collision of the cart moving towards right = 2.2 m/s
m₂ = mass of cart moving to left = 0.800 kg
v₂ = initial velocity before collision of the cart moving towards left = - 1.1 m/s
initial momentum of the system of carts before the collision is given as
P₁ = m₁ v₁ + m₂ v₂
P₁ = (0.500) (2.2) + (0.800) (- 1.1)
P₁ = 0.22 kg m/s
P₂ = momentum of system of carts after collision
As per conservation of momentum,
Momentum of system of carts after collision = Momentum of system of carts before collision
P₂ = P₁
P₂ = 0.22 kg m/s
Answer:
(a) 200.0628 N ; ( b) 4.08Kg
Explanation:
We know,
w = mg [here w= weight , m= mass , g= gravity]
now,
gravity on earth (g) =9.807 m/s²
mass of the spanner (m)=?
weight of the spanner on earth(w) = 40N
⇒ w = 40N
⇒m g =40N
⇒m = (40/g) Kg
⇒m= (40/9.807)Kg
∴m=4.08Kg
∴mass of the spanner on earth = 4.08Kg
We know,
Mass is the amount of matter in an object . So mass will remain same both on earth and jupiter.
So,
(b)The mass of the spanner on jupiter = 4.08Kg
Now,
The mass of the spanner on jupitar (m) = 4.08Kg
Gravity on jupiter (g*) = 5.g [5 times on earth]
= 5 . (9.807)m/s²
=49.035 m/s²
(a)
∴weight of the spanner on jupitar(w*) = m g*
=(4.08 x 49.035) N
=200.0628 N
Answer:
Via, vibration.
Source generate vibration, and air molecules vibrate, so kinetics and potential energy transfer
Mercury is 35.98 million miles from the sun