All categories

3 years ago

An aircraft engine takes in 8950 J of heat and discards 6150 J each cycle. Part A)

Physics

1 answer:

Alborosie3 years ago

4 0

Answer:

(a) 2800 J

(b) 31.28 %

Explanation:

Heat intake, Q1 = 8950 J

Heat discard, Q2 = 6150 J

(a) Work = intake heat energy - discarded heat energy

W = Q1 - Q2 = 8950 - 6150 = 2800 J

(b) Efficiency = 1 - Q2 / Q1

Efficiency = 1 - (6150 / 8950) = 0.3128 = 31.28%

You might be interested in

Motion combines the concepts of position change (length) and time. Which of the following combination of units is used to descri

noname [10]

Answer:

Length/time

Explanation:

As in the definition...Velocity is the rate of change of displacement...so hence

Velocity = Displacement/Time...where Displacement is length

Velocity = Length/Time

3 0

4 years ago

a person expended 500 newtons to move a full wheelbarrow 30 meters how much work was done? a person expended 500 newtons to move

stiv31 [10]

<span>A person expended 500 newtons to move a full wheelbarrow 30 meters how much work was done?

</span>In physics, a force is said to do work<span> if, when acting, there is a displacement of the point of application in the direction of the force. The work done would be calculated as follows:
</span>
W = F x d = 500 N (30 m) = 15000 J or 15 kJ

6 0

3 years ago

What is the fullform of SMPS ?

ira [324]

<h3>What is the fullform of SMPS ?</h3>

A switched-mode power supply (switching-mode power supply, switch-mode power supply, switched power supply, SMPS, or switcher) is an electronic power supply that incorporates a switching regulator to convert electrical power efficiently.

3 0

3 years ago

Read 2 more answers

An 18-cm-long bicycle crank arm, with a pedal at one end, is attached to a 20-cm-diameter sprocket, the toothed disk around whic

Tpy6a [65]

Answer:

Part a)

$a = 0.056 m/s^2$

Part b)

$L = 7.85 m$

Explanation:

Part a)

Angular speed of the pedal is changing from 60 rpm to 90 rpm in 10 s

so the angular acceleration is given as

$\alpha = \frac{\omega_2 - \omega_1}{\Delta t}$

so we will have

$\alpha = \frac{2\pi(\frac{90}{60}) - 2\pi(\frac{60}{60})}{10}$

$\alpha = 0.314 rad/s^2$

now the tangential acceleration of the pedal is given as

$a = r \alpha$

$a = 0.18 \times 0.314$

$a = 0.056 m/s^2$

Part b)

Total angular displacement made by the sprocket in the interval of 10 s is given as

$\theta = \frac{\omega_f + \omega_i}{2} t$

$\theta = \frac{2\pi (\frac{90}{60}) + 2\pi (\frac{60}{60})}{2}(10)$

$\theta = 78.5 radian$

now length of the chain passing over it is given as

$L = R\theta$

$L = 0.10 \times 78.5$

$L = 7.85 m$

6 0

4 years ago

A mercury barometer reads 745.0 mm on the roof of a building and 760.0 mm on the ground. Assuming a constant value of 1.29 kg/m3

Ipatiy [6.2K]

Answer:

The height of the building is 158.140 meters.

Explanation:

A barometer is system that helps measuring atmospheric pressure. Manometric pressure is the difference between total and atmospheric pressures. Manometric pressure difference is directly proportional to fluid density and height difference. That is:

$\Delta P \propto \rho \cdot \Delta h$

$\Delta P = k \cdot \rho \cdot \Delta h$

Where:

$\Delta P$ - Manometric pressure difference, measured in kilopascals.

$\rho$ - Fluid density, measured in kilograms per cubic meter.

$\Delta h$ - Height difference, measured in meters.

Now, an equivalent height difference with a different fluid can be found by eliminating manometric pressure and proportionality constant:

$\rho_{air} \cdot \Delta h_{air} = \rho_{Hg} \cdot \Delta h_{Hg}$

$\Delta h_{air} = \frac{\rho_{Hg}}{\rho_{air}} \cdot \Delta h_{Hg}$

Where:

$\Delta h_{air}$ - Height difference of the air column, measured in meters.

$\Delta h_{Hg}$ - Height difference of the mercury column, measured in meters.

$\rho_{air}$ - Density of air, measured in kilograms per cubic meter.

$\rho_{Hg}$ - Density of mercury, measured in kilograms per cubic meter.

If $\Delta h_{Hg} = 0.015\,m$ , $\rho_{air} = 1.29\,\frac{kg}{m^{3}}$ and $\rho_{Hg} = 13600\,\frac{kg}{m^{3}}$ , the height difference of the air column is:

$\Delta h_{air} = \frac{13600\,\frac{kg}{m^{3}} }{1.29\,\frac{kg}{m^{3}} }\times (0.015\,m)$

$\Delta h_{air} = 158.140\,m$

The height of the building is 158.140 meters.

5 0

3 years ago

Read 2 more answers