Answer:
Slope=
2.000
0.800
=0.400
x−intercept=
2
/5
=2.50000
y−intercept=
−5
/5
=
−1
1
=−1.00000
Step-by-step explanation:
STEP
1
:
Pulling out like terms
1.1 Pull out like factors :
6x - 15y - 15 = 3 • (2x - 5y - 5)
Equation at the end of step
1
:
STEP
2
:
Equations which are never true
2.1 Solve : 3 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Equation of a Straight Line
2.2 Solve 2x-5y-5 = 0
Tiger recognizes that we have here an equation of a straight line. Such an equation is usually written y=mx+b ("y=mx+c" in the UK).
"y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis.
In this formula :
y tells us how far up the line goes
x tells us how far along
m is the Slope or Gradient i.e. how steep the line is
b is the Y-intercept i.e. where the line crosses the Y axis
The X and Y intercepts and the Slope are called the line properties. We shall now graph the line 2x-5y-5 = 0 and calculate its properties
Answer:
The average speed of the entire trip is 8.5 miles per hour.
Step-by-step explanation:
Speed = Total Distance / Total Time
So we have to find the total distance and the total time taken .
1) From Gujranwala to Daska
speed= 25miles/hour distance = 15miles
Time taken = distance / speed
= 15/25= 0.6 hours
2) From Daska to Sialkot
speed= 40miles/hour distance = 15miles
Time taken = distance / speed
= 40/15= 2.67 hours
3 ) From Sialkot to Daska
speed= 30miles/hour distance = 15miles
Time taken = distance / speed
= 30/15= 2 hours
The total distance traveled to three places is = 15+ 15+15= 45miles
The Total time taken is = 0.6+ 2.67+ 2= 5.267=5.3 hours
Speed = Total Distance / Total Time
Speed= 45/ 5.3
= 8.49=8.5 miles per hour
The average speed of the entire trip is 8.5 miles per hour.
2 x (5-2)^3
2 x (3)^3
2 x 27
54
Do a t chart with the factors and then add the greatest common factor (GCF) with the fraction
I'm not totally sure, but it might be y= x/7.
