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3 years ago

Choose most accurate statement:

1 answer:

4 0

"Waves can exist in solids, liquids, and gases."
is the ONLY accurate statement.

The word "only" in the other 3 statements makes them
not accurate at all.

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According to this equation, F=ma, how much force is needed to accelerate an 82-kg runner at 7.5m/s2?

Murljashka [212]

You multiply the mass by the acceleration 82*7.5=615; that's what I would do

5 0

3 years ago

Read 2 more answers

Consider a uniformly charged sphere (an insulating sphere of radius R) and a spherical Gaussian surface with radius R 2 concentr

vodomira [7]

Answer:

Joe Mama

Explanation:

Reason? Joe mama half of her torso is radius u want to find......

5 0

3 years ago

If the escalator pulls you up a slope of 30.0o and moves with a velocity of 3.10m/s. What is the vertical component of your v

ioda

Answer:

$1.55\ \text{m/s}$

$2.68\ \text{m/s}$

Explanation:

v = Velocity of the elevator = 3.1 m/s

$\theta$ = Angle of the slope = $30^{\circ}$

Vertical component is given by

$v_y=v\sin\theta\\\Rightarrow v_y=3.1\sin30^{\circ}\\\Rightarrow v_y=1.55\ \text{m/s}$

The vertical component of the velocity is $1.55\ \text{m/s}$ .

Horizontal component is given by

$v_x=v\cos\theta\\\Rightarrow v_x=3.1\times \cos30^{\circ}\\\Rightarrow v_x=2.68\ \text{m/s}$

The horizontal component of the velocity is $2.68\ \text{m/s}$ .

8 0

3 years ago

A rock is thrown straight up. What is the net external force acting on the rock when it is at the top of its trajectory (ignorin

Nat2105 [25]

Answer:

b) Gravity

Explanation:

Gravity acts all of the time, when you apply force to a projectile it has to be more than the forces of the gravity and air resistance together so the projectile can move, when the rock is at the top of its trajectory the force that you applied at the beginning is getting lost, so the other forces (air resistance and gravity) make the rock fall to the floor.

8 0

3 years ago

A 5-kg ball collides inelastically head-on with a 10-kg ball, which is initially stationary. Which of the following statements i

NARA [144]

Answer:

The magnitude of the change of velocity the 5-kg ball experiences is less than that of the 10-kg ball.

Explanation:

In inelastic collision, the total momentum is always conserved after collision but the kinetic energy is reduced.

Momentum is Mass X velocity.

5 kg ball is in motion, while 10 kg ball is stationary; that is zero velocity.

The momentum of 10 kg ball before collision is zero while the momentum of 5 kg ball before collision is more than zero. Therefore, the magnitude of change in momentum will not be equal.

Next possible options are in kinetic Energy

Initial Kinetic energy = $\frac{1}{2}mu^2$

Final kinetic energy = $\frac{1}{2}mv^2$

Change in kinetic energy = Final Kinetic Energy - Initial Kinetic Energy

Change in kinetic energy of 5kg ball = $\frac{1}{2}mv^2 -\frac{1}{2}mu^2 = \frac{1}{2}m(v-u)^2$

Since the 5-kg ball has initial velocity (u), the magnitude of the change in velocity will be reduced.

Change in kinetic energy of 10kg ball:

the ball is initially at rest, therefore the initial velocity (u) will be zero (0)

Δ K.E = $\frac{1}{2}mv^2 -\frac{1}{2}mu^2 = \frac{1}{2}m(v-u)^2 = \frac{1}{2}m(v-0)^2 = \frac{1}{2}mv^2$

From the solution above, the magnitude of the change in velocity experienced by 10 kg ball is higher than 5 kg ball.

Hence, The magnitude of the change of velocity the 5-kg ball experiences is less than that of the 10-kg ball

4 0

4 years ago