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3 years ago

Choose most accurate statement:

1 answer:

4 0

"Waves can exist in solids, liquids, and gases."
is the ONLY accurate statement.

The word "only" in the other 3 statements makes them
not accurate at all.

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Plane-polarized light is incident on a single polarizing disk, with the direction of E0 parallel to the direction of the transmi

Vladimir [108]

Answer: $65.9^{\circ}$

Explanation:

Given

Intensity must be reduced by a factor of 6

Intensity is given by $I=I_o\cos ^2\theta\\$

Substitute $I$ by $\frac{I_o}{6}$

$\Rightarrow \dfrac{I_o}{6}=I_o\cos ^2\theta\\\\\Rightarrow \cos^2\theta =\dfrac{1}{6}\\\\\Rightarrow \cos \theta=\dfrac{1}{\sqrt{6}}\\\\\Rightarrow \theta=65.9^{\circ}$

So, the disk must be rotated by an angle of $65.9^{\circ}$ .

7 0

3 years ago

Would standing at the top of a slide be kinetic or potential?

sergeinik [125]

It would be potiental because your not moving

5 0

3 years ago

Read 2 more answers

All are examples of electric forces except _________. A. a neutron pushing on another neutron B. an electron pushing on a proton

Contact [7]

Answer:

A) a neutron pushing on another neutron.

Explanation:

Neutrons have no charge, therefore, there is no electric force among them. Protons and electrons on the other hand do have electric charge (electrons negative charge and protons positive charge) that generate electric forces between them that can be repelling forces (if the charges are of the same sign), or attractive forces (if the charges are of opposite signs).

6 0

4 years ago

All of the following devices are used to create an open circuit EXCEPT a:

Brrunno [24]

Answer:

I think its a fuse because everything else makes sense and is used in electrical circuits and the fuse is the only one that stands out to me ¯\_(ツ)_/¯

4 0

3 years ago

A battery is connected to a light bulb in a circuit. There is a current of 2 A in the light bulb.

Georgia [21]

Answer:

Resistance of the light bulb = 1.33 ohm (Approx.)

Explanation:

Given:

Current in electric bulb = 2 Amp

Voltage in battery = 1.5 Volt

Find:

Resistance of the light bulb

Computation:

Resistance = Voltage / Current

Resistance of the light bulb = Voltage in battery / Current in electric bulb

Resistance of the light bulb = 2 / 1.5

Resistance of the light bulb = 1.33 ohm (Approx.)

5 0

3 years ago