Answer:
The negative electrode of a battery has an excess of positive charge
Explanation:
This is because in every battery, there is a negative electrode ( cathode ) and only positive charge is deposited on it.
For other statements:
Batteries donot store electric charge but they store chemical energy
Some batteries donot use metals for the flow of electrons, but some use hydrogen gas at a pressure of 1 atmosphere.
Answer:
<u>Given</u><em> </em><em>-</em><em> </em><u>M</u><u> </u><u>=</u><u> </u>20 kg
k = 0.4
F = 200 N
<u>To </u><u>find </u><u>-</u><u> </u> acceleration
<u>Solution </u><u>-</u><u> </u>
F= kMA
200 = 0.4 * 20 * acceleration
200 = 8 * a
a = 8/200
a = 0.04 m s²
<h3>a = 0.04 m s²</h3>
Answer:
D) 763 nm
Explanation:
Calculation for the wavelength of light
Using this formula
Wavelength of light=Delta Y*Distance / Length
Where,
Delta Y represent the 2nd order bright fringe
Length represent the distance between both the slits and the screen
Distance represent the Distance between the slits
Let note that cm to m = (4.2) x 10^-2 and mm to m= ( 0.0400x 10^-3)
Now Let plug in the formula
Wavelength of light=[(4.2 x 10^-2m)(0.0400 x 10^-3m) / 2(1.1m)]*10^-7 meters
Wavelength of light=[(0.042m) (0.0004m)/2.2m]*10^-7 meters
Wavelength of light =(0.0000168m/2.2m)*10^-7 meters
Wavelength of light =7.63 *10^-7 meters
Wavelength of light =763 nm
Therefore the Wavelength of light will be 763 nm
Answer:
The ratio is 9.95
Solution:
As per the question:
Amplitude, ![y_{m} = 8.4\ cm](https://tex.z-dn.net/?f=y_%7Bm%7D%20%3D%208.4%5C%20cm)
Wavelength, ![\lambda = 5.3\ cm](https://tex.z-dn.net/?f=%5Clambda%20%3D%205.3%5C%20cm)
Now,
To calculate the ratio of the maximum particle speed to the speed of the wave:
For the maximum speed of the particle:
![v_{m} = y_{m}\times \omega](https://tex.z-dn.net/?f=v_%7Bm%7D%20%3D%20y_%7Bm%7D%5Ctimes%20%5Comega)
where
= angular speed of the particle
Thus
![v_{m} = 2\pi fy_{m}](https://tex.z-dn.net/?f=v_%7Bm%7D%20%3D%202%5Cpi%20fy_%7Bm%7D)
Now,
The wave speed is given by:
![v = f\lambda](https://tex.z-dn.net/?f=v%20%3D%20f%5Clambda)
Now,
The ratio is given by:
![\frac{v_{m}}{v} = \frac{2\pi fy_{m}}{f\lambda}](https://tex.z-dn.net/?f=%5Cfrac%7Bv_%7Bm%7D%7D%7Bv%7D%20%3D%20%5Cfrac%7B2%5Cpi%20fy_%7Bm%7D%7D%7Bf%5Clambda%7D)
![\frac{v_{m}}{v} = \frac{2\pi \times 8.4}{5.3} = 9.95](https://tex.z-dn.net/?f=%5Cfrac%7Bv_%7Bm%7D%7D%7Bv%7D%20%3D%20%5Cfrac%7B2%5Cpi%20%5Ctimes%208.4%7D%7B5.3%7D%20%3D%209.95)
The strength of an electromagnet can be altered by increasing the number of coils around the core. The more times the coil is wrapped, the stronger the electromagnet is.
Your answer is: B) Increasing the number of coils around the core
Have an amazing day and stay hopeful!