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3 years ago

Kinetic Energy HELP! Brainly included

Physics

1 answer:

Talja [164]3 years ago

6 0

Answer:

Explanation:

When you dropping the swing, it increases the kinetic energy. In the middle, that is when it is at it's fullest potential. As it makes its way up, it pushes again the gravitational force, and soon, the swing will stop at the top for a VERY SHORT AND SMALL period of time. That is when it is at it's very weakest point, making the answer, indeed, A.

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3 years ago

A 4.00 m long, massless beam rests horizontally on a support 3.00 m from the left

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If the beam is in static equilibrium, meaning the Net Torque on it about the support is zero, the value of x₁ is 2.46m

Given the data in the question;

Length of the massless beam; $L = 4.00m$

Distance of support from the left end; $x = 3.00m$

First mass; $m1 = 31.3 kg$

Distance of beam from the left end( m₁ is attached to ); $x_1 = ?$

Second mass; $m_2 = 61.7 kg$

Distance of beam from the right of the support( m₂ is attached to ); $x_1 = 0.273m$

Now, since it is mentioned that the beam is in static equilibrium, the Net Torque on it about the support must be zero.

Hence, $m_1g( x-x_1) = m_2gx_2$

we divide both sides by $g$

$m_1( x-x_1) = m_2x_2$

Next, we make $x_1$ , the subject of the formula

$x_1 = x - [ \frac{m_2x_2}{m_1} ]$

We substitute in our given values

$x_1 = 3.00m - [ \frac{61.7kg\ * \ 0.273m}{31.3kg} ]$

$x_1 = 3.00m - 0.538m$

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Therefore, If the beam is in static equilibrium, meaning the Net Torque on it about the support is zero, the value of x₁ is 2.46m

Learn more; brainly.com/question/3882839

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3 years ago

When did agriculture first began?

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3 years ago

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