Question

A flat circular loop of radius 0.10 m is rotating in a uniform magnetic field of 0.20 T. Find the magnetic flux through the loop when the plane of the loop and the magnetic field vector are perpendicular.'

Answer 1

Answer:

$\phi=6.28\times10^{-3}\;\;weber$

Explanation:

Given,

Magnetic field $B=0.2\;\;T$

Radius $r=0.1\;\;m$

The angle between the area vector and magnetic field is 0 degree, because the direction of area vector is always perpendicular to the plane.

$\phi=BAcos\theta\\\phi=o.2\times\pi (0.1)^2\times cos0^o\\\phi=0.00628\;\;weber\\\phi=6.28\times10^{-3}\;\;weber$