Answer:
B. 4.29s
Explanation:
If the man appears to move 12.4m/s when the boat appears to move 11m/s, it means that the man moves 1.4m on the boat (12.4-11=1.4). So if the man moves 1.4m per second then it will take him 6/1.4=4.29s to move 6 m relative to the boat.
Hope this helped!
Answer:
High amplitude is equivalent to loud sounds.
Explanation:
Answer:
Select the answer that states:
<em>VX = constant, and ay = -g</em>
Explanation:
In the case of an object undergoing projectile motion, such motion is divided in two analysis. The vertical analysis uses kinematic equations associated with an accelerated motion under the constant acceleration of gravity, and the horizontal analysis is that of a uniform motion at constant velocity.
Therefore the projectile motion uses the velocity in the horizontal (x-direction) as constant. and the vertical motion (associated with the y-axis) a motion with acceleration equal to "g".
Then, the corect answer is the one that states:
"<em>VX = constant, and ay = -g</em>"
Answer:
See below ~
Explanation:
The fact that water is attracted to itself, a property called <u>cohesion</u>, leads to another important property, the liquid form of water is <u>more</u> dense than the solid form. As water solidifies into ice, the molecules must move apart in order to fit in to a crystal lattice structure, causing water to expand as it freezes. Because of this, <u>ice floats</u> and water sinks, which keeps the oceans liquid and prevents them from freezing solid from the bottom up.
Answer:
50m; 0m/s.
Explanation:
Given the following data;
Initial velocity = 20m/s
Acceleration, a = - 4m/s²
Time, t = 5secs
To find the displacement, we would use the second equation of motion;
![S = ut + \frac {1}{2}at^{2}](https://tex.z-dn.net/?f=%20S%20%3D%20ut%20%2B%20%5Cfrac%20%7B1%7D%7B2%7Dat%5E%7B2%7D)
Substituting into the equation, we have;
![S = 20*5 + \frac {1}{2}*(-4)*5^{2}](https://tex.z-dn.net/?f=%20S%20%3D%2020%2A5%20%2B%20%5Cfrac%20%7B1%7D%7B2%7D%2A%28-4%29%2A5%5E%7B2%7D)
![S = 100 + (-2)*25](https://tex.z-dn.net/?f=%20S%20%3D%20100%20%2B%20%28-2%29%2A25)
![S = 100 - 50](https://tex.z-dn.net/?f=%20S%20%3D%20100%20-%2050)
Displacement, S = 50m
Next, to find the final velocity, we would use the third equation of motion;
Where;
- V represents the final velocity measured in meter per seconds.
- U represents the initial velocity measured in meter per seconds.
- a represents acceleration measured in meters per seconds square.
<em>Substituting into the equation, we have;</em>
Final velocity, V = 0m/s
<em>Therefore, the displacement of the bus is 50m and its final velocity is 0m/s.</em>