The net force on the object as described is; 58.84N
Two forces acting on the object are;
- The <em>applied force and the frictional force.</em>
In essence; the frictional force can be evaluated as;
- Frictional force; = coefficient × Weight of object.
- Frictional force = 0.21 × 20 × 9.8.
- Frictional force = 41.16N
- The Net force = Applied force - frictional force
Net Force = 58.84 N.
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According to Newton's second Law of motion, if the mass of an object is 10 kg and the force is 10 newtons, then the acceleration is 1m/s².
<h3>How to calculate acceleration?</h3>
The acceleration of a moving body can be calculated by dividing the force of the body by its mass.
According to this question, the mass of an object is 10 kg and the force is 10 newtons, then the acceleration can be calculated as follows:
acceleration = 10N ÷ 10kg
acceleration = 1m/s²
Therefore, according to Newton's second Law of motion, if the mass of an object is 10 kg and the force is 10 newtons, then the acceleration is 1m/s².
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Answer:
c large, spherical body that orbits in a clear path around a star
Explanation:
you can not say b because the sun is a star and you cant say a and d because all planets are not made of rock and all planets are not made of gas
Answer:
Maximum height reached by the rocket, h = 202.62 meters
Explanation:
It is given that,
Initial speed of the model rocket, u = 56.5 m/s
Constant upward acceleration, 
Distance traveled by the engine until it stops, d = 198.8 m
Let v is the speed of the rocket when the engine stops. It can be calculated using the third equation of motion as :
v = 63.02 m/s
At the maximum height, v = 0 and the engine now decelerate under the action of gravity, a = -g. Let h is the maximum height reached by the rocket.
Again using third equation of motion as :
h = 202.62 meters
So, the maximum height reached by the rocket is 202.62 meters. Hence, this is the required solution.
