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KiRa [710]
3 years ago
11

A satellite is orbiting Earth in an approximately circular path. It completes one revolution each day (86,400 seconds). Its orbi

tal distance is 22,500 kilometers from the Earth's center. What is the satellite's average speed?
Physics
1 answer:
Ray Of Light [21]3 years ago
5 0

Well, speed is always relative to some reference, and you haven't
specified the reference.  Also, you haven't specified the "tilt" of the
satellite's orbit relative to the Earth's equator.

So I'm going to pick the ones I like for both items:

-- For the satellite's average speed, I choose the reference
to be the center of the little satellite-TV dish on the corner of
my neighbor's garage roof.

-- For the satellite's orbital inclination, I choose zero.  That is,
the satellite's orbit is directly over Earth's equator. 

If you'll allow me those two assumptions, then your bird is
a communications satellite, located at the magic latitude
and distance from Earth where its orbital revolution matches
the Earth's rotation.  Viewed from anywhere on Earth, the
satellite's average speed is zero, and it appears to hang
motionless in the sky.

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tresset_1 [31]

Answer:

Part a)

Reading = 2.00 kg

Part b)

Reading = 2.00 kg

Part c)

Reading = 4.04 kg

Part d)

from t = 0 to t = 4.9 s

so the reading of the scale will be same as that of weight of the block

Then its speed will reduce to zero in next 3.2 s

from t = 4.9 to t = 8.1 s

The reading of the scale will be less than the actual mass

Explanation:

Part a)

When elevator is ascending with constant speed then we will have

F_{net} = 0

T - mg = 0

T = mg

So it will read same as that of the mass

Reading = 2.00 kg

Part b)

When elevator is decending with constant speed then we will have

F_{net} = 0

T - mg = 0

T = mg

So it will read same as that of the mass

Reading = 2.00 kg

Part c)

When elevator is ascending with constant speed 39 m/s and acceleration 10 m/s/s then we will have

F_{net} = ma

T - mg = ma

T = mg + ma

Reading is given as

Reading = \frac{mg + ma}{g}

Reading = 2.00\frac{9.81 + 10}{9.81}

Reading = 4.04 kg

Part d)

Here the speed of the elevator is constant initially

from t = 0 to t = 4.9 s

so the reading of the scale will be same as that of weight of the block

Then its speed will reduce to zero in next 3.2 s

from t = 4.9 to t = 8.1 s

The reading of the scale will be less than the actual mass

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3 years ago
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iris [78.8K]

I just did it the answer is..... B.cobwebs

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Luda [366]

Answer:

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Explanation:

The first thing will be to draw a figure showing the condition,

Lets takeI attractive force as +ve and repulsive force as - ve and thereafter calculating net force on outer left wire due to other wires, net force comes out to be - ve which tells us that force is repulsive, hence direction of force is away from wire as shown in figure in the attachment.

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The answer is A. The Sun and all the planets revolve around Earth.

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