The answer would be East. Negative particle. if that reads west then the opposite is east.
Answer:
The expression for the initial speed of the fired projectile is:
![\displaystyle v_0=\frac{M+m}{m}(2gL[1-cos(\theta)]^{\frac{1}{2}})](https://tex.z-dn.net/?f=%5Cdisplaystyle%20v_0%3D%5Cfrac%7BM%2Bm%7D%7Bm%7D%282gL%5B1-cos%28%5Ctheta%29%5D%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%29)
And the initial speed ratio for the 9.0mm/44-caliber bullet is 1.773.
Explanation:
For the expression for the initial speed of the projectile, we can separate the problem in two phases. The first one is the moment before and after the impact. The second phase is the rising of the ballistic pendulum.
First Phase: Impact
In the process of the impact, the net external forces acting in the system bullet-pendulum are null. Therefore the linear momentum remains even (Conservation of linear momentum). This means:
(1)
Second Phase: pendular movement
After the impact, there isn't any non-conservative force doing work in al the process. Therefore the mechanical energy remains constant (Conservation Of Mechanical Energy). Therefore:
(2)
The height of the pendulum respect L and θ is:
(3)
Using equations (1),(2) and (3):
(4)
The initial speed ratio for the 9.0mm/44-caliber bullet is obtained using equation (4):

Answer:
Explanation:
The melting point of the solid is 80°C
Vapor point of the liquid is 140°C
What happens to particles of X when heated from 70°C to 85°C?
- Firstly, there would be a phase change from solid to liquid.
- Below the melting point, a substance will exist as a solid.
- With increase in thermal energy inputted by heat, as the temperature climbs above the melting point, it changes to the liquid.
- When the solid begins to heat up, the particles of X starts vibrating about their fixed point.
- At they melting point, they break lose and flow to form a liquid.
- The particles will have more kinetic energy.