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3 years ago

14)

1 answer:

6 0

Watt is a unit for power that is also equal to J/s. We therefore need to convert the minutes to seconds first before answering. Every minute is comprised of 60 seconds. Therefore, 3 minutes are composed of 180 seconds. Multiplying the number of seconds to the given power will give us,
Work = Power x time
= (1500 J/s) x (180 s)
= 270,000 J
Therefore, the answer is letter D.

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A singly charged positive ion that has a mass of 6.07 ? 10-27 kg moves clockwise with a speed of 1.18 ? 104 m/s. the positively

mezya [45]

B = 0.018 T Ans,

Since, it is moving in a circular path, thus, centripetal force will act on it i.e.
F = $\frac{ mv^{2} }{r}$
where, m is the mass of the object, v is the velocity and r is the radius of circular path.

And, since a positive charge is moving, it will create magnetic force which is equal to F = qvB
where q is the charge, v is the velocity of the particle and B is the magnetic field.
Now, the two forces will be equal,
i.e. $\frac{ mv^{2} }{r}$ = qvB
⇒ $\frac{ mv }{r}$ = qB
⇒B = $\frac{ mv }{qr}$
<span>putting the values, we get,
</span>
use q = 1.6 * 10^ -19
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3 years ago

Problem 9.49: Air enters the turbine of a gas turbine at 1200 kPa, 1200 K, and expands to 100 kPa in two stages. Between the sta

Nitella [24]

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

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3 years ago

The drag force on a falling coffee filter can be modeled as a linear function with respect to velocity, F⃗ D =−bv, where b is a

nordsb [41]

Newton's second law and graphical analysis allow us to find the correct answer for the measure of the constant b is:

D) Stack several filters to change the mass measure the acceleration of the system.

Newton's second law establishes a relationship between the net force, the mass and the acceleration of the bodies.

∑ F = m a

Where the bold letters indicate vectors, F is the force, m the mass and the acceleration of the body.

They indicate that the drag force on the filters is

F = - b v

Where b is a positive constant that depends on the shape and area of the filter and v is the speed of the filter.

Let's write Newton's second law.

W - fr = ma

W -bv = ma

In the experiment the students indicate that they can measure the position, velocity and acceleration of the body.

Based on the above, if we place several filter weights and measure their speed and acceleration in each case, we can make a graph of velocity versus acceleration, we can take the value of the constant b from the slope.

Let's analyze the different answers:

A) False. The constant b depends on the shape of the filter therefore it must be kept constant.

B) False. The constant depends on the area, so it must be kept constant.

C) May be. In this case, since we have the terminal velocity, the acceleration is zero, Newton's second law remains.

B v - W = 0

b = $\frac{W}{v}$

The problem with the method is the difficulty of measuring the compression terminal velocity.

D) True. According to the discussion of the velocity versus acceleration. graph, the constant b is equal to the slope of the graph.

E) May be. The problem with this method is finding a reliable value for the terminal velocity.

In conclusion, using Newton's second law and graphical analysis we can find the correct answer for the measure of the constant b is:

D) Stack several filters to change the mass measure the acceleration of the system.

Learn more here: brainly.com/question/2441565

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2 years ago

Which of the following changes would decrease the coefficient of friction needed for this ride?

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Friction occurs between two contacting surfaces. The coefficient of friction is very much dependent on the roughness of these surfaces. Some of the many ways in which the coefficient can be lessened or decreased are to lubricate the surface or make it shiny by eliminating the spikes which caused the roughness.

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These compounds created a hole in the ozone layer by the following reactions:

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The last 2 reactions can repeat in a radical mechanism and explain why these compounds are so harmful to the ozone layer.

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4 years ago