To solve this problem we will apply the concepts related to dynamic equilibrium. The vertical component of the tension is equivalent to the centripetal Force while the horizontal component of the tension is equivalent to the weight, therefore we will have the two equations,

$Tsin\alpha = \frac{mv^2}{r}$

$Tcos\alpha = mg$

Our values are,

$v = 43ft/s = 13.11m/s$

$r = 212ft = 64.62m$

Therefore if we divide both equation we have,

$tan \alpha = \frac{v^2}{rg}$

Replacing,

$tan\alpha = \frac{13.11^2}{(64.62)(9.8)}$

$tan\alpha = 0.2714$

$\alpha = tan^{-1} (0.2714)$

$\alpha = 15.18\°$

Therefore the angle required is 15.18°

6 0

2 years ago

PLEASE HELP I WILL GIVE BRALINEST

maria [59]

1. acceleration i believe
2.more time the father they get (if that makes sense)

3 0

2 years ago

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Microwave ovens emit waves of about 2450 MHz. What is the wavelength of this light?

Vedmedyk [2.9K]

12.24 cm

Considering the frequency of 2,450 MHz, the wavelength of microwave oven radiation is about 12 cm and the quantum energy of a microwave photon is about 1 x 10-5 eV.

4 0

2 years ago