Answer:
8.73
Explanation:
The concentration of acetic acid can be determined as follows:






Moles of
= 
=0.0090 moles
Moles of 
= 0.0090 moles
The equation for the reaction can be expressed as :
----->

Concentration of
ion = 
= 
= 0.052 M
Hydrolysis of
ion:
----->


⇒ 
= 
As K is so less, then x appears to be a very infinitesimal small number
0.052-x ≅ x





![[OH] = x =0.535*10^{-5}](https://tex.z-dn.net/?f=%5BOH%5D%20%3D%20x%20%3D0.535%2A10%5E%7B-5%7D)
![pOH = -log[OH^-]](https://tex.z-dn.net/?f=pOH%20%3D%20-log%5BOH%5E-%5D)
![pOH = -log[0.535*10^{-5}]](https://tex.z-dn.net/?f=pOH%20%3D%20-log%5B0.535%2A10%5E%7B-5%7D%5D)

pH = 14 - pOH
pH = 14 - 5.27
pH = 8.73
Hence, the pH of the titration mixture = 8.73
Answer:
H2 < CH3Cl < HF
Explanation:
The intermolecular forces are the forces that bond the molecules together in a substance. There are three types of these forces:
- Dipole induced -dipole induced, or London dispersion -> Is the weakest and is presented in nonpolar molecules, in which a dipole is induced and so the molecules are joined together;
- Dipole-dipole -> Is stronger than the London dispersion and occurs in a polar molecule. In this case, the dipole already exists (partial positive and negative charges), so the poles are attracted;
- Hydrogen bond -> It's the strongest and is formed when the hydrogen is bonded with a higher electronegativity element (F, O, and N).
So, the molecule of H2 is linear and formed by the same element, so, is nonpolar, and has London dispersion forces. The molecule of CH3Cl has 3 nonpolar bonds (C-H), and one polar bond (C-Cl), so it's polar and has dipole-dipole forces. And the HF molecule has hydrogen bonds.
*A polar bond is a bond formed by elements with different electronegativities.
Engine is it ok ksndjsjja
<span>First set up the equation 39.33g/100g = x/1.28g and that'll give you how much sodium is in each 100g of the mix.
39.33g *1.28g= 100g * x
x = 0.503424g
x = Amount of sodium per 100g of the mix
Now 2.4g / 0.503424 = 4.7674
Multiply by 100 and you get 476.7353g</span>