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3 years ago

Four children pull on the same stuffed toy at the same time yet there is no net force on the toy. How is this possible.

Physics

2 answers:

uysha [10]3 years ago

7 0

Answer:

If the net force in the stuffed toy is zero, this means that the forces that the children apply on the toy cancel each other.

This can happen if, for example, two kids pull by one side with a force F and the other two kids pull by the other side with the same force -F (the minus sign is because the direction is the opposite)

Then, the total force is F + (-F) = F - F = 0

Stels [109]3 years ago

3 0

Answer:

Net force is Zero.

Explanation:

If all forces that are equal and opposite are exerted on an object the resulting force will be Zero.

You might be interested in

If an object has a mass of 20 grams and a volume of 40 cm3, what is its density in g/cm3?

sattari [20]

Density = Mass/Volume
So, given mass = 20 g and volume = 40 cm^3
By substituting in above equation, Density = 20/40 = 0.5 g/cm^3
Hope it helps.

3 0

3 years ago

An area experiences thunderstorms with high winds and a drop in temperature. Which weather event most likely occurred? A. A stat

gavmur [86]

Answer:

C a fast-moving cold front moved through the area.

Explanation:

This is because, since there is a there is a thunderstorm and high winds in the area, this can only be caused by a fast moving front. Also there is a temperature drop, this can only be caused by the fast moving cold front since a cold front has a low temperature.

Thus, for the area to experience thunderstorms with high winds and a drop in temperature, a fast-moving cold front moved through the area.

5 0

3 years ago

An egg is thrown nearly vertically upward from a point near the cornice of a tall building. The egg just misses the cornice on t

diamong [38]

Answer:

1. 18.5m/s

2. 17.5 m

3. 0 at its highest point

4. Direction is downwards

Explanation:

1. This egg is thrown vertically from a height

Yo = 0. This egg then falls to the point y = -30.0 at t = 5seconds

Y-Yo = V0t - 1/2gt²

-30-0 = V0(5)-1/2(9.8)(5²)

-30 = 5v0 - 4.9x25

-30 = 5V0 - 122.5

-30+122.4 = 5v0

V0 = 92.5/5

= 18.5m/s

this is the initial speed of the egg

2. When the egg is at a maximum height it would have a velocity equal to 0

V² = V0² - 2*g*y

V = 0, V0 = 18.5, g = 9.8

0 = 18.5²-2x9.8*y

342.25-19.6y = 0

342.25 = 19.6y

Divide through by 19.6

Y = 342.25/19.6

Y = 17.5m

this value is how high it rises above starting point

The magnitude of velocity is = 0 at its highest point

This egg falls under gravity. Therefore the acceleration due to gravity has a constant magnitude and direction. Magnitude = 9.8m/s and it's direction is downwards.

5. Please check attachment for graph