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3 years ago

Please answer the question above and pick an answer choice from the ones provided

Mathematics

1 answer:

Ira Lisetskai [31]3 years ago

3 0

Answer:

1,2 and 4 are equivalents. 3 is not equivalent

2P-I, mark that one :l

Step-by-step explanation:

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F(x) = 4* How to evaluate

photoshop1234 [79]

Answer:fx=4

Step-by-step explanation:

fx=4

7 0

3 years ago

2) Tara is trying to find the nth term of the arithmetic sequence 5,8,11, and 14…. Which expression can Tara use to find the nth

juin [17]

Answer:

Below in bold.

Step-by-step explanation:

Nth term an = a1 + d(n - 1) where a1 = term 1 and d = common difference.

Here a1 = 5 and d = 8-5 = 3.

So an = 5 + 3(n - 1)

15th term a15

= 5 + 3(15 - 1)

= 5 + 42

= 47.

4 0

3 years ago

15x -5 = 45 + 19 what is x

SCORPION-xisa [38]

Answer:

x equals 4.6

Step-by-step explanation:

if u need explanation plz tell me so i can help

4 0

3 years ago

Read 2 more answers

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.

Oliga [24]

Answer:

$\displaystyle 1)48.2 \: \: \text{sec}$

$\rm \displaystyle 2)3021.6 \: m$

Step-by-step explanation:

<h3>Question-1:</h3>

so when flash down occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

$\displaystyle - 4.9 {t}^{2} + 229t + 346 = 0$

to solve the equation can consider the quadratic formula given by

$\displaystyle x = \frac{ - b \pm \sqrt{ {b}^{2} - 4 ac} }{2a}$

so let our a,b and c be -4.9,229 and 346 Thus substitute:

$\rm\displaystyle t = \frac{ - (229) \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

remove parentheses:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

simplify square:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}$

simplify multiplication:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 6781.6} }{ - 9.8}$

simplify Substraction:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 45659.4} }{ - 9.8}$

by simplifying we acquire:

$\displaystyle t = 48.2 \: \: \: \text{and} \quad - 1.5$

since time can't be negative

$\displaystyle t = 48.2$

hence,

at 48.2 seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

$\displaystyle x _{ \text{max}} = \frac{ - b}{2a}$

let a and b be -4.9 and 229 respectively thus substitute:

$\displaystyle t _{ \text{max}} = \frac{ - 229}{2( - 4.9)}$

simplify which yields:

$\displaystyle t _{ \text{max}} = 23.4$

now plug in the maximum t to the function:

$\rm \displaystyle h(23.4)- 4.9 {(23.4)}^{2} + 229(23.4)+ 346$

simplify:

$\rm \displaystyle h(23.4) = 3021.6$

hence,

about 3021.6 meters high above sea-level the rocket gets at its peak?

5 0

3 years ago

Need help what are the classifications of each system

ratelena [41]

You can graph them on Desmos, then use this attachment to find out the classification.

In the first system, they're the same line and have infinitely many solutions, therefore the answer is consistent, dependent.

In the second system, they're parallel lines with no solution, therefore the answer is inconsistent.

In the third system, they intersect and they have one solution, therefore the answer is consistent, independent.

In the fourth system, they're the same line and have infinitely many solutions, therefore the answer is consistent, dependent.

5 0

3 years ago