Using accurate measurements, using pure chemicals and performing the reaction under the most ideal conditions is important to get a valuable percent yield.
<h3>How we calculate the percent yield?</h3>
Percent yield of any chemical reaction is define as the ratios of the actual yield to the theoretical yield of the product and multiply by the 100.
To get the high percent yield or actual yield of any reaction, we have to perform the reaction under ideal condition because if we not use the standard condition then we get the low rate of reaction. Reactants should be present in the pure form as impurity make unwanted products and reduce the productivity of main product and accurate amount of reactants also important for the spontaneous reaction.
Hence, options (a), (b) & (c) are correct.
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The answer is A beautiful
I believe it is b. you only want to change one thing at a time so you know which one thing caused the effect
Answer:
V = 0.2714 mL
Explanation:
Henry's Law:
∴ Kh CO2 = 0.034 M/atm ....The Henry's constant
∴ Partial pressure: P CO2 = 3.7 atm
⇒ <em>C</em> CO2 = P CO2 / Kh
⇒ <em>C</em> CO2 = 3.7 atm / 0.034 M/atm = 108.823 M (mol/L)
∴ molar mass CO2 = 44.01 g/mol
⇒ mol CO2 = (1.3 E3 mg)(g/1000 mg)(mol/44.01 g) = 0.03 mol CO2
volumen solution:
⇒ V sln = (0.03 mol)(L/108.823 mol) = 2.714 E-4 L
⇒ V sln = 0.2714 mL
The answer is: mass is 40.17 kilograms.
d = 0.758 g/mL; density of fuel.
V = 14.0 gal; volume.
A gallon is a unit of volume in both the US customary and imperial systems of measurement. The US gallon is defined as 231 cubic inches (3.785 liters).
1 gal = 3785.41 mL.
V = 14 gal · 3785.41 mL:
V = 52995.74 mL.
m = 52995.74 mL · 0.758 g/mL.
m = 40170.77 g; mass of fuel.
m = 40170.77 g ÷ 1000 g/kg.
m = 40.17 kg.
