Question

Select the two values of x that are roots of this equation x^2+3x-3=0 Apex

Answer 1

Answer:

C, and D are both roots of this equation

Answer 2

Answer:

The two values of x that are roots are:

$x_{1} = \frac{-3 + \sqrt{21} }{2}$

$x_{2} = \frac{-3 - \sqrt{21} }{2}$

Step-by-step explanation:

A cuadratic function has the form $ax^{2} + bx +c = 0$

To calculate the roots of the cuadratic equation $x^{2} + 3x -3 = 0$ you have to solve the formula:

$x = \frac{-b}{2a}$ ±$\frac{\sqrt{b^{2} -4ac} }{2a}$

In this case, a =1, b=3 and c= -3

Replacing the values of a,b and c in the formula:

$x = \frac{-3}{(2)(1)}$ ± $\frac{\sqrt{(3)^{2} - (4)(1)(-3) } }{(2)(1)}$

Solving the mathematic operations:

x = $\frac{-3}{2}$ ± $\frac{\sqrt{9 + 12 } }{2}$

The two roots are:

$x_{1} = \frac{-3 + \sqrt{21} }{2}$

$x_{2} = \frac{-3 - \sqrt{21} }{2}$