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lesya [120]
3 years ago
9

When you hold an object with a positive electric charge near an object with a

Chemistry
1 answer:
solmaris [256]3 years ago
7 0

Answer:

A positively charged object will exert a repulsive force upon a second positively charged. This repulsive force will push the two objects apart while a negatively charged object will exert a repulsive force upon a second negatively charged object. Objects with like charge repel each other

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What is the average kinetic energy of 1 mole of a gas at -32 degrees Celsius? (R = 8.314 J/K-mol)
romanna [79]

Answer:

3.01 x 103 J

Explanation:

To determine the average kinetic energy of a gas, it is necessary to use the equation, KE = 3/2 RT. The value of R, multiplied by the temperature, and multiplied by 3/2, can provide the average kinetic energy of the gas.

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Why does a solid change to a liquid when heat is added
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Why did Rutherford choose alpha particles in his experiment?
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Balance this equation-<br> _P4 + _02 --&gt; _P203
ikadub [295]

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Explanation:

If you insist on filling in the first blank you can put a one.

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3 years ago
What temperature will the water reach when 10.1 g CaO is dropped into a coffee cup containing 157 g H2O at 18.0°C if the followi
Zepler [3.9K]

Answer:

Final temperature attained by water = 34.6°C

Explanation:

The reaction of CaO and H₂O is an <em>exothermic reaction</em>. The equation of reaction is given below:

CaO + H₂O ----> Ca(OH)₂

The quantity of heat given off, ΔH°rxn = 64.8KJ/mol = 64800J/mol

Number of moles of CaO = mass/molar mass, where molar mass of Ca0 = 56g/mol, mass of CaO = 10.1g

Number of moles of CaO = 10.1g/56g/mol =0.179moles

Quantity of heat given off by 0.179 moles = 64800 *0.179 = 11599.2J/mol

Using the formula, <em>Quantity of heat, q = mass * specific heat capacity * temperature rise.</em>

mass of mixture = (10.1 + 157)g = 167.1g, Initial temperature = 18.0°C

Final temperature(T₂) - Initial temperature(T₁) = Temperature rise

11599.2J/mol = 167.1g * 4.18J/g·°C * ( T₂ - 18.0°C)

11599.2 = 698.478T₂ - 12572.604

11599.2 + 12572.604 = 698.478T₂

698.478T₂ = 24171.804

T₂ = 34.6°C

Therefore, final temperature attained by water = 34.6°C

6 0
3 years ago
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