Answer:
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M₁ = mass of water = 75 g
T₁ = initial temperature of water = 23.1 °C
c₁ = specific heat of water = 4.186 J/g°C
m₂ = mass of limestone = 62.6 g
T₂ = initial temperature of limestone = ?
c₂ = specific heat of limestone = 0.921 J/g°C
T = equilibrium temperature = 51.9 °C
using conservation of heat
Heat lost by limestone = heat gained by water
m₂c₂(T₂ - T) = m₁c₁(T - T₁)
inserting the values
(62.6) (0.921) (T₂ - 51.9) = (75) (4.186) (51.9 - 23.1)
T₂ = 208.73 °C
in three significant figures
T₂ = 209 °C
Given what we know, the ability of water to absorb more heat than the other substances mentioned is a reflection of its high boiling point.
<h3>What do we mean by boiling point?</h3>
This is the temperature at which the substance boils, and subsequently evaporates. Having a higher boiling point means that the substance will be able to absorb much more heat than that of a substance with a lower boiling point.
Therefore, Water molecules have a higher boiling point than molecules of similar size, such as ammonia and methane, reflecting its capacity to absorb large amounts of heat.
To learn more about water molecules visit:
brainly.com/question/11405437?referrer=searchResults
