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2 years ago

An __________ is defined as a substance that ionizes in water.

Chemistry

2 answers:

lianna [129]2 years ago

4 0

An electrolyte is defined as a substance that ionizes in water.

Allisa [31]2 years ago

4 0

It would be both "the process of becoming an ion" and "a polar covalent molecule forming ions"

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The reaction gives off heat energy, so it is an __________ reaction

Alex_Xolod [135]

Since the reaction gives off heat energy it is considered to be an exothermic reaction

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2 years ago

Which of the following is not a natural

Morgarella [4.7K]

Answer:

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3 years ago

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How many moles are in 7.2x10^15 atoms of Pb?

fiasKO [112]

<h3>Answer:</h3>

1.2 × 10⁻⁸ mol Pb

<h3>General Formulas and Concepts:</h3>

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Atomic Structure

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

Using Dimensional Analysis

<h3>Explanation:</h3>

Step 1: Define

[Given] 7.2 × 10¹⁵ atoms Pb

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

[DA] Set up: $\displaystyle 7.2 \cdot 10^{15} \ atoms \ Pb(\frac{1 \ mol \ Pb}{6.022 \cdot 10^{23} \ atoms \ Pb})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 1.19562 \cdot 10^{-8} \ mol \ Pb$

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

1.19562 × 10⁻⁸ mol Pb ≈ 1.2 × 10⁻⁸ mol Pb

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2 years ago

What size volumetric flask would you use to create a 1.00M solution using 166.00 g of KI?

mr Goodwill [35]

Answer:

A 1 liter volumetric flask should be used.

Explanation:

First we convert 166.00 g of KI into moles, using its molar mass:

Molar mass of KI = Molar mass of K + Molar mass of I = 166 g/mol

166.00 g ÷ 166 g/mol = 1 mol KI

Then we calculate the required volume, using the definition of molarity:

Molarity = moles / liters

Liters = moles / molarity

1 mol / 1.00 M = 1 L

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2 years ago

PLS HELP ASAP

LenaWriter [7]

Answer:

B) burning wood

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2 years ago

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