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3 years ago

What is the angle o in the triangle below? (Hint: Use an inverse trigonometric function.)

Physics

1 answer:

Shalnov [3]3 years ago

5 0

Answer:

D. 66.4

Explanation:

So this problem uses SOHCAHTOA or the three trig functions.

Specifically this uses cosine, because it has an adjacent and a hypotenuse.

First you would determine what to do on the calculator, and since the problem is saying so, use the inverse cosine button. This will give you a angle measure from the decimal.

On a calculator, type in cos^-1(6/15). I used 6/15 because cosine is adjacent over hypotenuse. This will give you 66.4, which is D on the answers.

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A bicyclist of mass 60kg supplies 340W of power while riding into a 5 m/s head wind. The frontal area of the cyclist and bicycle

NikAS [45]

Answer:

87.1 mph

Explanation:

We are given that

Mass,m=60 kg

Power,P=340 W

Speed,v=5 m/s

Area, $A=0.344 m^2$

Drag coefficient, $C_d=0.88$

Coefficient of rolling resistance, $\mu_r=0.007$

Friction force, $f=\mu_rmg=0.007\times 60\times 9.8=4.1 N$

Where $g=9.8 m/s^2$

Let speed of cyclist=v'

Drag force, $F_d=\frac{1}{2}\rho_{air}AC_dv^2$

Density of air, $\rho_{air}=1.225 kg/m^3$

$F_d=\frac{1}{2}\times 1.225\times 0.344\times 0.88(5)^2=4.635N$

Power,P= $(F_d+f)\times v'$

$340=(4.1+4.635) v'=8.735v'$

$v'=\frac{340}{8.735}=38.9m/s$

$v'=87.1 mph$

1 m=0.00062137 miles

1 hour=3600 s

7 0

3 years ago

A sensitive gravimeter at a mountain observatory finds that the free-fall acceleration is 0.0055 m/s2 less than that at sea leve

pshichka [43]

Gs*rs^2 = gm*rm^2
rm = rs*√gs/gm 
rm = 6370*√9.83/(9.83-0.009) = 6372.92 
mountain observatory is placed at an altitude worth 2920 m asl

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3 years ago

Which of the following is not a part of the appendicular skeleton

Bingel [31]

Answer:

Hyoid

Explanation:

The hyoid is located in the neck area, not the limbs.

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A student shoots a spitball with a perfectly horizontal velocity of 9.7 m/s from a height of 1.8 meters. How long will it take f

sergejj [24]

Answer:A student shoots a spitball with a perfectly horizontal velocity of 9.7 m/s from a height of 1.8 meters. How long will it take for the spitball to hit the ground?

(ignore air resistance) (include units and correct number of significant figures)

Explanation:La respuesta es porque esa es la respuesta, la respuesta al número es 9.7 1.8 Divide =53.888

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3 years ago

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Luden [163]

Answer:

the answer is true

Explanation:

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2 years ago

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