Answer:
YFy = 0 = Ffsinθ + Fncosθ - Fw
Explanation:
From the base of the vector Fn, draw a vertical line. the small angle between this line and Fn is also theta. The component of Fn in the vertical direction is Fncos(theta).
Take a moment to picture extreme cases. Sine is 0 at 0 and 1 at 90. Cosine is 1 at 0 and 0 at 90.
Tilt the incline so that the box is on a flat surface. How much of the gravitational force is along the x direction of the floor.
Answer:
The width of the central bright fringe on the screen is observed to be unchanged is
Explanation:
To solve the problem it is necessary to apply the concepts related to interference from two sources. Destructive interference produces the dark fringes. Dark fringes in the diffraction pattern of a single slit are found at angles θ for which
Where,
w = width
wavelength
m is an integer, m = 1, 2, 3...
We here know that as as w are constant, then
We need to find , then
Replacing with our values:
Therefore the width of the central bright fringe on the screen is observed to be unchanged is
Answer:
a) 2cm³
b) 100 g/cm³
Explanation:
a- 9-7= 2cm³
b- 200 divided by 2= 100 g/cm³
Hope this helps... correct me if i'm wrong
Answer: idk that is a tough one!
Explanation: that is a hard question IDK
Answer:
Magnetic field, B = 0.88 T
Explanation:
It is given that,
The dimension of rectangular surface is 2.80 cm by 3.15 cm. The area of rectangular surface is,
Angle between the uniform magnetic field and the horizontal,
Magnetic flux,
Let B is the magnitude of magnetic field in which the rectangular surface is placed. It is given by :
is the angle between magnetic field and the area
Here,
B = 0.88 T
So, the magnitude of magnetic field is 0.88 T. Hence, this is the required solution.