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Sunny_sXe [5.5K]
3 years ago
8

Your teacher asks you to design an experiment that shows how plants respond to changes in their environment. You have two identi

cal plants to do your experiment, and you may add any other equipment of your choosing. Using the scientific method, design an experiment that meets your teacher’s criteria.
Match each step of the scientific method with a step of the experiment.

A. Make observations.

2. Ask a question.

3. Test the hypothesis.

4. Analyze the results, and make a conclusion.

5. Test or modify.

A. Put one plant under a white lightbulb, and
place the other plant under a red lightbulb.
Measure the growth of the two plants.

B. If you observe no change, repeat the experiment with different colors of lightbulbs. If there is a change, repeat the experiment for one or two more trials to ensure that the color of the lightbulb contributes to the change.


C. Do plants grow as well under a different
color of light?


D. Determine whether the plant grown under the white lightbulb or the plant grown under the red lightbulb grew better.


E. Plants grow well under sunlight or a lightbulb
with a hot, white light.

Can you put the letter with the number so I won’t get confused
Chemistry
2 answers:
tia_tia [17]3 years ago
6 0

Answer:

1.  Make observations.

Determine whether the plant grown under the white light bulb or the plant grown under the red light bulb grew better.

Observations are anything we notice which lead to a question in our mind.

2. Ask a question.

Do plants grow as well under a different color of light?

As this is a question being asked, hence it will be the question for the scientific method of research.

3. Test the hypothesis.

Put one plant under a white light bulb, and  place the other plant under a red light bulb.  Measure the growth of the two plants.

To test the hypothesis, experiments are performed. This is the experiment.

4. Analyze the results, and make a conclusion.

Plants grow well under sunlight or a light bulb  with a hot, white light.

After the experiments, the results are compiled and a conclusion is drawn.

5. Test or modify.

If you observe no change, repeat the experiment with different colors of light bulbs. If there is a change, repeat the experiment for one or two more trials to ensure that the color of the light bulb contributes to the change.

If our hypothesis does not come out to be true, then another hypothesis can be generated and tests be done for it.

Stels [109]3 years ago
6 0

Answer:

1.  Make observations.

Determine whether the plant grown under the white light bulb or the plant grown under the red light bulb grew better.

Observations are anything we notice which lead to a question in our mind.

2. Ask a question.

Do plants grow as well under a different color of light?

As this is a question being asked, hence it will be the question for the scientific method of research.

3. Test the hypothesis.

Put one plant under a white light bulb, and  place the other plant under a red light bulb.  Measure the growth of the two plants.

To test the hypothesis, experiments are performed. This is the experiment.

4. Analyze the results, and make a conclusion.

Plants grow well under sunlight or a light bulb  with a hot, white light.

After the experiments, the results are compiled and a conclusion is drawn.

5. Test or modify.

If you observe no change, repeat the experiment with different colors of light bulbs. If there is a change, repeat the experiment for one or two more trials to ensure that the color of the light bulb contributes to the change.

If our hypothesis does not come out to be true, then another hypothesis can be generated and tests be done for it.

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Calculate the enthalpy of the reaction
harkovskaia [24]

Answer : The enthalpy of the reaction is, -2552 kJ/mole

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given enthalpy of reaction is,

4B(s)+3O_2(g)\rightarrow 2B_2O_3(s)    \Delta H=?

The intermediate balanced chemical reactions are:

(1) B_2O_3(s)+3H_2O(g)\rightarrow 3O_2(g)+B_2H_6(g)     \Delta H_A=+2035kJ

(2) 2B(s)+3H_2(g)\rightarrow B_2H_6(g)    \Delta H_B=+36kJ

(3) H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)    \Delta H_C=-285kJ

(4) H_2O(l)\rightarrow H_2O(g)    \Delta H_D=+44kJ

Now we have to revere the reactions 1 and multiple by 2, revere the reactions 3, 4 and multiple by 2 and multiply the reaction 2 by 2 and then adding all the equations, we get :

(when we are reversing the reaction then the sign of the enthalpy change will be change.)

The expression for enthalpy of the reaction will be,

\Delta H=-2\times \Delta H_A+2\times \Delta H_B-6\times \Delta H_C-6\times \Delta H_D

\Delta H=-2(+2035kJ)+2(+36kJ)-6(-285kJ)-6(+44)

\Delta H=-2552kJ

Therefore, the enthalpy of the reaction is, -2552 kJ/mole

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