All categories

3 years ago

Which is the formula for diarsenic pentoxide?

Chemistry

2 answers:

Olenka [21]3 years ago

7 0

Formula for diarsenic pentoxide
As2O5

Nitella [24]3 years ago

7 0

The formula for diarsenic peroxide is: Ar₂O₅

You might be interested in

8. What is one sign that the water in your house is "hard?"

hodyreva [135]

Answer:

More than soap sc um, hard-to-remove scale or film is often due to hard water. Also, take a good look at your faucets or fixtures.

Explanation:

hope this helps :D

7 0

3 years ago

A solution contains 5.25 g of urea, CO(NH2)2 (a nonvolatile solute) and 0.100 kg of water. If the vapor pressure of pure water a

babymother [125]

Answer:

The vapor pressure of the solution is 23.3 torr

Explanation:

Step 1: Data given

Mass of urea = 5.25 grams

Mass of water = 0.100 kg = 100 grams

Temperature = 25.0 °C

Vapor pressure of water = 23.7 torr

Step 2: Calculate moles of water

Moles H2O = mass H2O / molar mass H2O

Moles H2O = 100 grams / 18.02 g/mol

Moles H2O = 5.55 moles

Step 3: Calculate moles of urea

Moles urea = 5.25 grams / 60.06 g/mol

Moles urea = 0.0874 moles

Step 4: Calculate mol fraction H2O

Mol fraction H2O = 5.55 moles / (5.55 + 0.0874)moles

Mol fraction H2O = 0.984

Step 5: calculate the vapor pressure of the solution

This means that you can use the mole fraction of water and the vapor pressure of pure water at 25° C to determine the vapor pressure of the solution.

Psol =Xwater * Pwater

⇒Psol = the vapor pressure of the solution

⇒Xwater =the mol fraction of water

⇒Pwater = the vapor pressure of pure water

Psol = 0.984 * 23.7 torr

Psol = 23.3 torr

The vapor pressure of the solution is 23.3 torr

3 0

4 years ago

In a certain compound of iron and oxygen, FexOy, it is found that a sample of this compound weighing 6.285 g contains 4.396 g of

saveliy_v [14]

Answer:

Formula of oxide is $Fe_{2}O_{3}$

Explanation:

The given compound consists of Fe and O.

So, mass of oxygen in sample = (mass of sample) - (mass of Fe in sample)

= (6.285 g ) - (4.396 g)

= 1.889 g

Molar mass of O = 16 g/mol and molar mass of Fe = 55.845 g/mol

So, ratio of number of moles of Fe and O (Fe : O)

= $\frac{4.396}{55.845}:\frac{1.889}{16}$

= 0.0787 : 0.118

= $1:\frac{0.118}{0.0787}$

= 1 : 1.5

= 2 : 3

So, formula of oxide is $Fe_{2}O_{3}$

5 0

3 years ago

Calculate the grams of solute in each of the following solution: 278 mL of 0.038 M Fe2(SO4)3

Goryan [66]

Answer: 4.22 grams of solute is there in 278 ml of 0.038 M $Fe_2(SO_4)_3$

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n}{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in L

Now put all the given values in the formula of molality, we get

$0.038M=\frac{n}{0.278L}$

$n=0.0105mol$

mass of $Fe_2(SO_4)_3$ = $moles\times {\text {Molar Mass}}=0.0105\times 399.88g/mol=4.22g$

Thus 4.22 grams of solute is there in 278 ml of 0.038 M $Fe_2(SO_4)_3$

3 0

4 years ago

Under which conditions would the solubility of a gas be greatest? A. high pressure and high temperature B. high pressure and low

LiRa [457]

Answer:

High pressure and low temperature.

Explanation:

8 0

3 years ago