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photoshop1234 [79]
3 years ago
14

What is the acceleration experienced by a car that takes 10s to reach 27m/s from rest

Physics
1 answer:
Lerok [7]3 years ago
5 0

|acceleration|  =  (change in speed) / (time for the change)

Change in the car's speed = (27 - 0) = 27 m/s
Time for the change  =  10 sec

|acceleration| = (27 m/s) / (10 s)  =  2.7 m/s² .

That's the magnitude of the car's acceleration.
We don't know anything about its direction.
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Why is it that the weight of an object weighing 1N air, weighs more when immersed in water ?
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There is no "why", because that's not what happens.  The truth is
exactly the opposite. 

Whatever the weight of a solid object is in air, that weight will appear
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The object is lifted by a force equal to the weight of the fluid it displaces.
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4 0
3 years ago
What is the objective lens?
Monica [59]

Answer:

The objective lens is an optical tool used to focus an image.

Explanation:

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3 years ago
How was bohr atomic model similar to Rutherford's model​
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6 0
4 years ago
Read 2 more answers
Q. A mass of 300g is lifted to a<br> height of 10m<br> 205 by a person. Calculate his work done
sergiy2304 [10]
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3 0
2 years ago
Vector A⃗ points in the negative y direction and has a magnitude of 5 km. Vector B⃗ has a magnitude of 15 km and points in the p
Alexxandr [17]

Answer:

magnitude of A − B =  15.81 km

Explanation:

Vector A points in the negative y-direction and has a magnitude of 5 km. Vector B points in the positive x-direction and has a  magnitude of 15 km.

According to Cartesian coordinate system, the resultant will start either from tail of A and ends at head of B and vice-versa.

A(0,-5)

B(15,0)

A - B = (-15 i - 5 j )

Magnitude of the vector is given by

|A - B| = \sqrt{(-15)^{2}+(-5)^{2}}

|A - B| = \sqrt{250}

|A - B| = 15.81 km

7 0
3 years ago
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