A 4.0-cm tall light bulb is placed at distance of 8.3 cm from a concave mirror having a focal length of 15.2 cm. Determine the i
mage distance and the image size. Also indicate the orientation of the image compared to the object as well as if it will be a real or virtual image.
1 answer:
Answer: the image distance is -18, 28 cm this means behind of the concave mirror. The image size is 2.2 higher that the original so it has 8.8 cm with the same orientation as original and it is a virtual imagen.
Explanation: In order to sove the imagen formation for a concave mirror we have to use the following equation:
1/p+1/q=1/f where p and q represents the distance to the mirror for the object and imagen, respectively. f is the focal length for the concave mirror.
replacing the values we obtain:
1/8.3+1/q=1/15.2
so 1/q=(1/15.2)-(1/8.3)=-54.7*10^-3
then q=-18.28 cm
The magnification is given by M=-q/p=-(-18,28)/8.3= 2.2
We also add a picture to see the imagen formation for this case.
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Answer:
Total momentum, p = 21.24 kg-m/s
Explanation:
Given that,
Mass of first piece,
Mass of the second piece,
Speed of the first piece, (along x axis)
Speed of the second piece, (along y axis)
To find,
The total momentum of the two pieces.
Solve,
The total momentum of two pieces is equal to the sum of momentum along x axis and along y axis.
The net momentum is given by :
p = 21.24 kg-m/s
Therefore, the total momentum of the two pieces is 21.24 kg-m/s.