<span>THE HIGHEST CONCENTRATION OF HYDROGEN IONS IS LOCATED IN THE INTER-MEMBRANE SPACE. HYDROGEN IONS REACH THE INTER-MEMBRANE SPACE THROUGH PROTEIN CHANNELS EMBEDDED IN THE MITOCHONDRIAL MEMBRANE. THE MAIN FUNCTION OF INTER MEMBRANEIS OXIDATIVE PHOSPHORLATON. ENERGY IS REQUIRED TO MOVE THE HYDROGEN IONS ACROSS THE MEMBRANE BECAUSE THE HYDROGEN IONS ARE MOVING AGAINST THE CONCENTRATION GRADIENT. H+ GOES AGAINST THE CONCENTRATION GRADIENT THE USE OF THE GRADIENT TO DRIVE ATP SYNTHASE. HYDOGEN IONS DRIVE ATP SYNTHASE IN PHTOSYNTHESIS. THIS HAPPENS WHEN HYDROGEN IONS GET PUSHED ACROSS THE MEMBRANE CREATING A HIGH CONCENTRATION INSIDE THE THYLAKOID.</span>
Answer:
The "unit" remaining after conversion is atoms.
This is a way to calculate the number of atoms, in an specific mass.
Explanation:
When you have a mass, multiplying the molar mass, "grams" are cancelled, so you finally obtained, number of moles.
Moles . atoms/mol, cancel the word mol so you will find out a number of atoms, present at the mass from, the begining.
For example, how many atoms are in 10 g of NaCl
Molar mass NaCl = Na mass + Cl mass
23 + 35.45 = 58.45 g/m
10 g . 1 / 58.45 mol/g . NA/ 1 mol = 3.42x10²⁰ atoms
NA = Avogadro number
Answer:
Impurities will be trapped in the crystals of the benzoic acid crystallized in this manner.
Explanation:
After benzoic acid is dissolved in hot water, it should have been allowed to cool gradually before it is transferred into an ice bath.
This gradual cooling will aid the separation of impurities so that when the vessel is now submerged in an ice bath, only pure benzoic acid is recrystalized.
If the vessel is immediately submerged into an ice bath, impurities will be trapped in the crystals of the benzoic acid.
Answer:
A) 6.00 mol.
B) 0.375 L or 375 mL
C) 6.00 M
Explanation:
Hello,
A) In this case, from the definition of molarity, we compute the moles for the given volume and concentration:
B) In this case, from the stock solution, the required volume is:
C) In this case, we apply the following formula for dilution process:
Thus, solving for the final molarity, we obtain:
Regards.
