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lutik1710 [3]
3 years ago
5

Find the acute angles between the curves at their points of intersection. (The angle between two curves is the angle between the

ir tangent lines at the point of intersection. Give your answers in degrees, rounding to one decimal place. Enter your answers as a comma-separated list.) y = 8x2, y = 8x3
Physics
1 answer:
ladessa [460]3 years ago
3 0

Answer:

1.190390345 degrees.

Explanation:

As stated in the problem that the angle between the two curves is also the angle between slopes of the two cures at the point of intersection, which is 1 (when we set two equation equal and solve for x).

We know, if you don't  you could verify it for yourself and it will be a nice mathematical exercise for you, that when there are two lines with slopes m_1 and m_2 then the angle between them and their two slopes has following relationship.

tan(\alpha ) = |\frac{m_2-m_1}{1+m_1m_2}|   where \alpha is angle between the two lines.

As it is clear that we can easily get the angle between the two curves if we know slopes at that point, which you will see in second is very straight forward to calculate.

Slopes are simply derivatives evaluated at the point of intersection and the two derivatives are D_1 16x and D_2 =24x^2, substituting x =1 we get, m_1 = 16 and m_2 = 24.

Now put m_1 and m_2 in this relationship, rearrange and solve for angle, it will come out to be

\alpha = 1.190390345 degrees.

that is our angle that we want to know between the two cures at the point of their intersection.

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A 5.00 g object moving to the right at 20.0 cm/s makes an elastic head-on collision with a 10.0 g object that is initially at re
marusya05 [52]

Answer: a) 6.67cm/s b) 1/2

Explanation:

According to law of conservation of momentum, the momentum of the bodies before collision is equal to the momentum of the bodies after collision. Since the second body was initially at rest this means the initial velocity of the body is "zero".

Let m1 and m2 be the masses of the bodies

u1 and u2 be their velocities respectively

m1 = 5.0g m2 = 10.0g u1 = 20.0cm/s u2 = 0cm/s

Since momentum = mass × velocity

The conservation of momentum of the body will be

m1u1 + m2u2 = (m1+m2)v

Note that the body will move with a common velocity (v) after collision which will serve as the velocity of each object after collision.

5(20) + 10(0) = (5+10)v

100 + 0 = 15v

v = 100/15

v = 6.67cm/s

Therefore the velocity of each object after the collision is 6.67cm/s

b) kinectic energy of the 10.0g object will be 1/2MV²

= 1/2×10×6.67²

= 222.44Joules

kinectic energy of the 5.0g object will be 1/2MV²

= 1/2×5×6.67²

= 222.44Joules

= 111.22Joules

Fraction of the initial kinetic transferred to the 10g object will be

111.22/222.44

= 1/2

3 0
4 years ago
A physical change occurs when a material changes shape or size but the composition of the material does not change. True or Fals
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It is true that a physical change occurs when a material changes shape or size, but the composition of the material does not change. The correct answer is True. 
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How long does it take lewis hamilton travelling at 156 mph to cover 16 miles?
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A wood block, after being given a starting push, slides down a ramp at a constant speed. what is the angle of the ramp above hor
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The solution for the problem is:

Constant speed means Fnet = 0. 
Let m = mass of wood block and Θ = angle of ramp; then if µk = 0.35 …

The computation would be:


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= arctan (0.35)

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