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Gekata [30.6K]
3 years ago
10

A positively charged particle moves through an electric field. As part of a complicated trajectory, the particle passes through

the points A and B. The electric potential of the two points is such that VB > VA. The electric force is the only force acting on the particle. What can be deduced about the speed, v, of the particle at the two points?
(A) The speed is equal at the two points.
(B) The speed is larger at A than at B.
(C) The speed is larger at B than at A.
Physics
1 answer:
kow [346]3 years ago
8 0

Answer:

(B) The speed is larger at A than at B.

Explanation:

Point B, the final point of the trajectory, has higher electric potential than point A, the initial point of the trajectory, so the electric potential energy of the charged particle increases, which means that its kinetic energy must be decreasing, thus the speed at B must be lower than the speed at A.

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A cylindrical insulated wire of diameter 5.0 mm is tightly wound 200 times around a cylindrical core to form a solenoid with adj
laiz [17]

Answer:

0.0016 T

Explanation:

Parameters given:

Diameter of wire = 5 mm = 0.005 m

Radius of wire, R = 0.0025 m

Number of turns, N = 200

Current through the wire, I = 0.10A

The magnitude of the magnetic field is given as:

B = (u₀NI) / (2πR)

Where u = magnetic permeability of free space.

B = (1.257 * 10⁻⁶ * 200 * 0.1) / (2 * π * 0.0025)

B = 0.0016 T

The magnitude of the Magnetic field is 0.0016 T.

3 0
4 years ago
Read 2 more answers
When advising a customer on the purchase of a new power supply, you should explain that if the power supply runs at peak perform
LiRa [457]

Answer: 30% more

Explanation:

7 0
3 years ago
A nurse pushes a cart by exerting a force on the handle at a downward angle of 36 degrees below the horizontal. the loaded cart
Troyanec [42]

Since it was stated that it must move at constant velocity, so the only force it must overpower is the frictional force.

So the equation is:

F cos θ = Ff

F cos 36 = 65 N

F = 80.34 N

 

<span>So the nurse must exert 80.34 N of force</span>

4 0
3 years ago
A 6.00-m long string sustains a three-loop standing wave pattern as shown. The wave speed is 2.00 × 102 m/s.What is the lowest p
KATRIN_1 [288]

Given:

The length of the string is l = 6 m

The speed of the wave is

v=2\times10^2\text{ m/s}

Required: Lowest possible frequency for the standing wave.

Explanation:

The lowest possible frequency is the fundamental frequency.

The fundamental frequency can be calculated by the formula

f=\frac{v}{2l}

On substituting the values, the fundamental frequency will be

\begin{gathered} f=\frac{2\times10^2}{2\times6} \\ =16.67\text{ Hz} \end{gathered}

Final Answer: The lowest possible frequency for standing waves on this string is 16.67 Hz

4 0
2 years ago
Select three different examples of accelerated motion. a body traveling in a straight line and increasing in speed a body travel
IrinaVladis [17]
This is the same question that I just answered.

Have present the definition of acceleration:

         a = Δv / Δt, this is change in velocity per unit of time.

a and v are in bold to mean that they are vectors.

1) a body traveling in a straight line and increasing in speed: CORRECT:

Acceleration is the change in velocity, either magnitude or direction or both. So, a body increasing in speed is accelerated.

2) a body traveling in a straight line and decreasing in speed: CORRECT

A decrease in speed is a change in velocity, so it means acceleration.

3) a body traveling in a straight line at constant speed: FALSE.

That body is not changing either direction or speed so its motion is not accelerated but uniform.

4) a body standing still : FALSE.

That body is not changind either direction or speed.

5) a body traveling at a constant speed and changing direction: CORRECT.

The change in direction means that the body is accelerated. The acceleration due to change in direction is named centripetal acceleration.
6 0
4 years ago
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