A positively charged particle moves through an electric field. As part of a complicated trajectory, the particle passes through
1 answer:
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Answer:
θ = tan⁻¹ ()
Explanation:
This problem must be solved using projectile launch ratios. Let's analyze the situation, the projectile explodes at the highest point, therefore we fear the height (i = h), the speed at this point is the same, but the direction changes, we are asked to find the smallest angle of the speed in the point of arrival with respect to the x-axis.
The speed at the arrival point (y = 0)
v² = vₓ² + v_y²
Let's see how this angle changes, for two extreme values:
* The particle that falls from the point of explosion, in this case the speed is vertical
v = v_y
the angle with the horizontal is 90º
* The particle leaves horizontally from the point of the explosion, the initial velocity is horizontal
vₓ = v
the final velocity for y = 0
v_f = vₓ² + v_y²
therefore the angle has a value greater than zero and less than 90º
As they ask for the smallest angle, we can see that we must solve the last case
the output velocity is horizontal vₓ = v
Let's find the velocity when it hits the ground y = 0, with y₀ = h
=
- 2 g (y-y₀)
v_{y}^2 = - 2g (0- y₀)
let's calculate
v_{y}^2 = 2 9.8 h
we use trigonometry to find the angle
tan θ =
θ = tan⁻¹ ()
let's calculate
θ = tan⁻¹ ()
Answer:
Final temperature, T2 = 314.9 Kelvin
Explanation:
Given the following data:
Mass = 0.9kg
Initial temperature, T1 = 10°C to Kelvin = 10 + 273 = 283K
Quantity of heat = 120,000 J
Specific heat capacity = 4182 j/kgK
To find the final temperature;
Heat capacity is given by the formula;
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
dt represents the change in temperature.
Making dt the subject of formula, we have;
Substituting into the equation, we have;
dt = 31.9K
Now, the final temperature T2 is;
But, dt = T2 - T1
T2 = dt + T1
T2 = 31.9 + 283
T2 = 314.9 Kelvin