The change in velocity is 10 mi/h (4.47 m/s)
Explanation:
The change in velocity of the motorcyclist is given by

where
v is the final velocity
u is the initial velocity
In this problem, we have
u = 0 (the motorbike starts from rest)
v = 10 mi/h
Therefore, the change in velocity is

And keeping in mind that
1 mile = 1609 m
1 h = 3600 s
We can convert it into m/s:

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Answer:
Acceleration a ≤ 3 m/s^2
the greatest acceleration that the truck can have without losing its load is 3 m/s^2
Explanation:
For the truck to accelerate without losing its load.
Acceleration force of truck must be less than or equal to the maximum friction force between the truck bed and the load.
Fa ≤ F(friction)
But;
Fa = mass × acceleration
Fa = ma
ma ≤ F(friction)
a ≤ (F(friction))/m ......1
Given;
Fa = mass × acceleration
Fa = ma
mass m = 800 kg
F(friction) = 2400 N
Substituting the given values into equation 1;
a ≤ F(friction)/m
a ≤ 2400N/800kg
a ≤ 3 m/s^2
the greatest acceleration that the truck can have without losing its load is 3 m/s^2