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Firdavs [7]
3 years ago
14

How many grams of Ar are there in 2.25 moles of Ar?

Chemistry
2 answers:
Arada [10]3 years ago
5 0
There will be 89.865 grams of Ar. If you put it in sig figs, it will be rounded to 89.9g At.

Flura [38]3 years ago
4 0

Answer:There will be 89.865 grams of Ar.. If you put it in figs, it will be rounded to 89.9g At..

Explanation:

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A projectile is fired with speed v0 at an angle theta from the horizontal from the horizontal as shown in the figure.
irga5000 [103]

Answer:

v₀ = √(2gH/(sin²θ)) = (sin θ)√(2gH)

v₀ = √(gR/(sin2θ))

Explanation:

An image of the artillery officer, the hill and path of motionof the projectile is attached to this solution.

Given, R, H, g and θ (theta)

Using the equations of motion, we can get the initial velocity v₀

First of, we need to resolve this motion into the vertical and horizontal axis.

The horizontal component of the initial velocity, v₀ₓ = v₀ cos θ

Vertical component of the initial velocity, v₀ᵧ = v₀ sin θ

When the projectile reaches maximum height, Velocity at max height, vₕ = 0m/s

From equations of motion,

vₕ = v₀ᵧ - gt

0 = v₀ sinθ - gt

t = v₀ sinθ/g

This is the time taken to reach maximum height. The time take to comolete the toyal flight, T = 2t = (2v₀ sinθ)/g

The maximum height to be reached, H can be calculated from the equations of motion too

H = vₕt - 0.5gt² = 0 - 0.5g((v₀ sinθ)/g)²

H = (0.5g v₀² sin²θ)/g²

H = (v₀² sin²θ)/2g

The range, or horizontal distance to be covered by the projectile, R, will be calculated using the horizontal component of the initial Velocity, v₀ₓ = v₀ cos θ, this horizontal velocity is constant all through the motion, so, no acceleration in the horizontal direction.

R = v₀ₓT =  (v₀ cos θ)((2v₀ sinθ)/g)

R = (v₀²(2cosθsinθ)/g)

2cosθsinθ = sin2θ

R = v₀²(sin2θ)/g

So, writing v₀ in terms of all the other parameters,

v₀ = √(2gH/(sin²θ)) =  (sinθ)√(2gH

v₀ = √(gR/(sin2θ))

4 0
2 years ago
How many moles of \ce{Fe2O3}FeX 2 ​ OX 3 ​ will be produced from 27.0 \text{ g}27.0 g27, point, 0, start text, space, g, end tex
ira [324]

Answer : The number of moles of Fe_2O_3  produced will be, 0.241 moles.

Solution : Given,

Mass of Fe = 27.0 g

Molar mass of Fe = 56 g/mole

First we have to calculate the moles of Fe.

\text{ Moles of }Fe=\frac{\text{ Mass of }Fe}{\text{ Molar mass of }Fe}=\frac{27.0g}{56g/mole}=0.482moles

Now we have to calculate the moles of Fe_2O_3

The balanced chemical reaction is,

4Fe+3O_2\rightarrow 2Fe_2O_3

From the reaction, we conclude that

As, 4 mole of Fe react to give 2 mole of Fe_2O_3

So, 0.482 moles of Fe react to give \frac{0.482}{4}\times 2=0.241 moles of Fe_2O_3

Thus, the number of moles of Fe_2O_3  produced will be, 0.241 moles.

6 0
2 years ago
Can some tell me plz
valentina_108 [34]

Answer: stay the same because it's a solid.

Explanation:

5 0
3 years ago
Read 2 more answers
1. Related to the number of particles in a gram of
Romashka-Z-Leto [24]

Answer:

Avogadro's number or Avogardro’s constant

Explanation:

I’m pretty sure this is correct if it’s not I’m sorry lol.

6 0
1 year ago
3. A thin lead apron is used to protect patients from harmful X rays. If the sheet measures 75.0 cm by 55.0 cm by 0.10 cm, and t
DanielleElmas [232]

Answer:

4.67 kg

Explanation:

Given data

  • Dimensions of the lead sheet: 75.0 cm by 55.0 cm by 0.10 cm
  • Density of lead: 11.3 g/cm³

Step 1: Calculate the volume of the sheet

The volume of the sheet is equal to the product of its dimensions.

V = 75.0 cm \times  55.0 cm \times 0.10 cm = 413 cm^{3}

Step 2: Calculate the mass of the sheet

The density (ρ) is equal to the mass divided by the volume.

\rho = \frac{m}{V} \\m = \rho \times V = \frac{11.3g}{cm^{3} }  \times 413cm^{3} = 4.67 \times 10^{3} g = 4.67 kg

6 0
2 years ago
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