Answer:
Primary active transport
Explanation:
In a cell, the movement of molecules like calcium ions (Ca²⁺), <em>to a region having high solute concentration from a region having low solute concentration, through the cell membrane requires metabolic energy</em> and is known as Primary active transport.
It is given that the concentration of calcium in the cell (0.3%) is greater than the concentration of calcium in the fluid surrounding the cell (0.1%). <em><u>So the calcium ions move into the cell and the cell obtains more calcium. </u></em>
<u>Therefore, the cell obtains more calcium by the process of Primary active transport.</u>
Answer:Even if your door is closed, you would still smell the odors because of the space under the door and the space that is needed to close the door.
Explanation:
Answer:
A. True
B. False
C. False
D. True
E. False
Explanation:
A. The proximal histidine covalently binds iron.
This statement is true because the proximal histidine is covalently bonded to the fifth coordination position of iron in myoglobin
B. The distal histidine covalently binds oxygen.
This statement is false because the distal histidine interacts with the oxygen covalently bonded to the sixty coordination position of iron by means of a hydrogen bond not a covalent bond.
C. The distal histidine binds iron
This statement is false because the distal histidine is not bonded to iron but to oxygen but stabilizes the oxygen bonded to iron
D. Free heme binds CO with the Fe, C and O atoms in a linear array.
This statement is true because free heme has more affinity for CO than O2 as it has the least steric hindrance when the Fe, C, and O atoms lie in a straight line. On the other hand, when O2 binds to free heme, the axis of the oxygen molecule is positioned at an angle to the Fe-O bond thereby producing significant steric hindrance.
E. The iron in heme binds the oxygen atom of CO.
This statement is false because the iron in heme binds to the carbon atom, C, of CO rather than to oxygen atom.
Answer:
The correct answer is option B.
Explanation:
Michaelis–Menten 's equation:
![v=V_{max}\times \frac{[S]}{(K_m+[S])}=k_{cat}[E_o]\times \frac{[S]}{(K_m+[S])}](https://tex.z-dn.net/?f=v%3DV_%7Bmax%7D%5Ctimes%20%5Cfrac%7B%5BS%5D%7D%7B%28K_m%2B%5BS%5D%29%7D%3Dk_%7Bcat%7D%5BE_o%5D%5Ctimes%20%5Cfrac%7B%5BS%5D%7D%7B%28K_m%2B%5BS%5D%29%7D)
![V_{max}=k_{cat}[E_o]](https://tex.z-dn.net/?f=V_%7Bmax%7D%3Dk_%7Bcat%7D%5BE_o%5D)
v = rate of formation of products
[S] = Concatenation of substrate = ?
![[K_m]](https://tex.z-dn.net/?f=%5BK_m%5D)
= Michaelis constant
= Maximum rate achieved
= Catalytic rate of the system
= initial concentration of enzyme
We have :
[S] =?
![v=V_{max}\times \frac{[S]}{(K_m+[S])}](https://tex.z-dn.net/?f=v%3DV_%7Bmax%7D%5Ctimes%20%5Cfrac%7B%5BS%5D%7D%7B%28K_m%2B%5BS%5D%29%7D)
![\frac{V_{max}}{4}=V_{max}\times \frac{[S]}{(0.0050 M+[S])}](https://tex.z-dn.net/?f=%5Cfrac%7BV_%7Bmax%7D%7D%7B4%7D%3DV_%7Bmax%7D%5Ctimes%20%5Cfrac%7B%5BS%5D%7D%7B%280.0050%20M%2B%5BS%5D%29%7D)
![[S]=\frac{0.005 M}{3}=1.7\times 10^{-3} M](https://tex.z-dn.net/?f=%5BS%5D%3D%5Cfrac%7B0.005%20M%7D%7B3%7D%3D1.7%5Ctimes%2010%5E%7B-3%7D%20M)
So, the correct answer is option B.
This is because it has a full outer valence shell! so there are 8 electrons and that means it doesn't have the urge the gain anymore
