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skad [1K]
3 years ago
9

1. Determine the number of atoms in 2.50 mol Zn.2.so molznxlmolo"6.02x10​

Chemistry
1 answer:
klemol [59]3 years ago
4 0

Answer:

15.1  × 10²³ atoms

Explanation:

Given data:

Number of moles of Zn = 2.50 mol

Number of atoms = ?

Solution:

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

For 2.50 mole of Zn:

one mole of zinc = 6.022 × 10²³ atoms

2.50 × 6.022 × 10²³ atoms

15.1  × 10²³ atoms

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Answer:

The correct answer is "11.44 ml".

Explanation:

Molarity,

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As we know,

⇒  Molarity=\frac{No. \ of \ moles }{Volume \ of \ solution}

or,

⇒  No. \ of \ moles=Molarity\times Volume

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⇒                         =0.2\times 1

⇒                         =0.2 \ moles

Now,

⇒  No. \ of \ moles=\frac{Mass \ taken}{Molecular \ mass}

or,

⇒  Mass \ taken=No. \ of \ moles\times Molecular \ mass

⇒                      =0.2\times 60.05

⇒                      =12.01 \ gram

hence,

⇒  Density= \frac{Mass }{Volume}

or,

⇒  Volume=\frac{Mass}{Density}

⇒                =\frac{12.01}{1.05}

⇒                =11.44 \ ml

7 0
3 years ago
What is the concentration of a phosphoric acid solution of a 25.00 mL sample if the acid requires 42.24 mL of 0.135 M NaOH for n
kaheart [24]
0.0760 m

do this by:

finding the moles of NaOH which will be <span>5.702 E -3 m
</span>
next find the moles of H3PO4 which will be <span>1.90 E -3 m</span><span>
calulcate </span>25 ml sample molarity = 0.07603 m, just put 0.0760<span>

</span>
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Hope it help!

~Mqddie
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