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spayn [35]
3 years ago
11

What force accelerates a 500 kg object at 5 m/s2? A. 25000 N B. 2000 N C. 250 N D. 2500 N

Physics
1 answer:
alisha [4.7K]3 years ago
3 0

Apply Newton's second law of motion:

F = ma

F = force, m = mass, a = acceleration

Given values:

m = 500kg

a = 5m/s²

Plug in and solve for F:

F = 500(5)

F = 2500N

Choice D

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A 0.12-mu or micro FF capacitor, initially uncharged, is connected in series with a 10-kohm resistor and a 12-V battery of negli
miv72 [106K]

Answer:

The time is 2.8 ms.

Explanation:

Given that,

Capacitor = 0.12 μF

Resistance = 10 kohm

Voltage = 12 V

Charge Q = 0.9 Q₀

We need to calculate the time constant

Using formula of time constant

T=RC

Put the value into the formula

T=10\times10^{3}\times0.12\times10^{-6}

T=0.0012\ sec

We need to calculate the time

Using formula of time

Q=Q_{0}(1-e^{\frac{-t}{T}})

Put the value into the formula

0.9Q_{0}=Q_{0}(1-e^{\frac{-t}{0.0012}})

ln (0.1)=\dfrac{-t}{0.0012}

t=0.00276\ sec

t=2.8\ ms

Hence, The time is 2.8 ms.

6 0
4 years ago
If a 0.15 kg ball falls and has a KE of 20 J just before striking the ground, from what height did it fall. A. 1.36m B. 3m C. 13
RUDIKE [14]
According to the conservation of mechanical energy, the kinetic energy just before the ball strikes the ground is equal to the potential energy just before it fell. 

Therefore, we can say KE = PE
We know that PE = m·g·h

Which means KE = m·g·h

We can solve for h:

h = KE / m·g
   = 20 / (0.15 · 9.8) 
   = 13.6m

The correct answer is: the ball has fallen from a height of 13.6m.

5 0
3 years ago
A 26.0 g ball is fired horizontally with initial speed v0 toward a 110 g ball that is hanging motionless from a 1.10 m -long str
mart [117]

Answer:

7.3 ms^{-1}

Explanation:

Consider the motion of the ball attached to string.

In triangle ABD

Cos50 = \frac{AB}{AD} \\Cos50 = \frac{AB}{L}\\AB = L Cos50

height gained by the ball is given as

h = BC = AC - AD \\h = L - L Cos50\\h = 1.10 - 1.10 Cos50\\h = 0.393 m

M  = mass of the ball attached to string = 110 g

V = speed of the ball attached to string just after collision

Using conservation of energy

Potential energy gained = Kinetic energy lost

Mgh = (0.5) M V^{2} \\V = sqrt(2gh)\\V = sqrt(2(9.8)(0.393))\\V = 2.8 ms^{-1}

Consider the collision between the two balls

m  = mass of the ball fired = 26 g

v_{o} = initial velocity of ball fired before collision = ?

v_{f} = final velocity of ball fired after collision = ?

using conservation of momentum

m v_{o} = MV + m v_{f}\\26 v_{o} = (110)(2.8) + 26 v_{f}\\v_{f} = v_{o} - 11.85

Using conservation of kinetic energy

m v_{o}^{2} = MV^{2} + m v_{f}^{2} \\26 v_{o}^{2} = 110 (2.8)^{2} + 26 (v_{o} - 11.85)^{2} \\v_{o} = 7.3 ms^{-1}

3 0
3 years ago
It is determined that a certain light wave has a wavelength of 3.012 x 10-12 m. The light travels at 2.99 x 108 m/s. What is the
gayaneshka [121]

Answer:

id.k

Explanation:

3 0
3 years ago
Why do scientists use the scientific method when completing experiments.
polet [3.4K]

Answer:

Scientists use the scientific method to collect measurable, empirical evidence in an experiment related to a hypothesis.

Explanation:

8 0
3 years ago
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