Question

Three batteries are connected in series so that the total voltage is 54 volts. The voltage of the first battery is twice the voltage of the second and 1/3 the voltage of the third battery. Find the actual voltage of each battery.

Answer 1

Answer:

$v_1 = 12 volts$

$v_2 = 6 volts$

$v_3 = 36 volts$

Explanation:

As we know that all the batteries are in series

so the net voltage of all three batteries is given as

$V = v_1 + v_2 + v_3$

now we know that

$v_1 = 2v_2$

$v_1 = \frac{1}{3}v_3$

now plug in all the values in it

$54 = v_1 + \frac{v_1}{2} + 3v_1$

$54 = 4.5 v_1$

$v_1 = 12 volts$

now we have

$v_2 = 6 volts$

$v_3 = 36 volts$