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3 years ago

predict where an unknown element that has these properties could fit in the periodic table 62 protons and electrons

1 answer:

5 0

Position of element in periodic table is depend on the electronic configuration of element.

Element with 62 electrons has following electronic configuration:
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 4f6 6s2

From above electronic configuration, it can be seen that highest value of principal quantum number, where electron is present, is 6. Hence, element belongs to 6th period.

Further, last electron has entered f-orbital, hence it is a f-block element. Position of f-block element is the bottom of periodic table.

Further, there are 6 electrons in f-orbital. Hence, it is the 6th f-block element in 6th period of periodic table.

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Which term describes the molecule shown below?

Kisachek [45]

Answer: Saturated alkane

Explanation:

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3 years ago

10 points) Which is larger? Ba²+ or Ba explain

lutik1710 [3]

Answer:

Ba is larger than Ba2 + B a 2 + because it has two more electrons.

Explanation:

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1 year ago

What is the volume occupied by 112.0 grams of mercury

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Answer:

V= 8.235 ml

Explanation:

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3 years ago

Assume that concentrated aqueous NH3 has a density of 0.252 g/mL (0.252 g of NH3 per mL of liquid). Calculate the volume of NH3

Kobotan [32]

The question is incomplete, here is the complete question:

Assume that concentrated aqueous NH₃ has a density of 0.252 g/mL (0.252 g of NH₃ per mL of liquid). Calculate the volume of NH₃ required to contain 0.442 mol?

Answer: The volume of ammonia required is 29.82 mL

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of ammonia = 17 g/mol

Moles of ammonia = 0.442 moles

Putting values in above equation, we get:

$0.442mol=\frac{\text{Mass of ammonia}}{17g/mol}\\\\\text{Mass of ammonia}=(0.442mol\times 17g/mol)=7.514g$

To calculate the volume of ammonia, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of ammonia = 0.252 g/mL

Mass of ammonia = 7.514 g

Putting values in above equation, we get:

$0.252g/mL=\frac{7.514g}{\text{Volume of ammonia}}\\\\\text{Volume of ammonia}=\frac{7.514g}{0.252g/mL}=29.82mL$

Hence, the volume of ammonia required is 29.82 mL

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3 years ago

According to the electron sea theory, what happens when a collection of metal atoms are in close proximity to each other?

lys-0071 [83]

The correct answer is A. All electrons become free and separate from the nuclei. In metallic bonds, the electrons of the metal atoms are delocalized. The electron in the electron sea can freely roam around or are free to flow.

8 0

3 years ago