All categories

2 years ago

predict where an unknown element that has these properties could fit in the periodic table 62 protons and electrons

1 answer:

5 0

Position of element in periodic table is depend on the electronic configuration of element.

Element with 62 electrons has following electronic configuration:
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 4f6 6s2

From above electronic configuration, it can be seen that highest value of principal quantum number, where electron is present, is 6. Hence, element belongs to 6th period.

Further, last electron has entered f-orbital, hence it is a f-block element. Position of f-block element is the bottom of periodic table.

Further, there are 6 electrons in f-orbital. Hence, it is the 6th f-block element in 6th period of periodic table.

You might be interested in

What is the Scientific notation for 8,950,000

Tatiana [17]

The scientific notation for 8,950,000 is
8.95 × 10^6

6 0

2 years ago

I messed up Èeeeeeeeeeeeeeeeeeeee

Triss [41]

Answer:

Explanation:

6 0

1 year ago

Silver chloride is formed by mixing silver nitrate and barium chloride solutions. What volume of 1.50 M barium chloride solution

konstantin123 [22]

Answer:

1.22 mL

Explanation:

Let's consider the following balanced reaction.

2 AgNO₃ + BaCl₂ ⇄ Ba(NO₃)₂ + 2 AgCl

The molar mass of silver chloride is 143.32 g/mol. The moles corresponding to 0.525 g are:

0.525 g × (1 mol/143.32 g) = 3.66 × 10⁻³ mol

The molar ratio of AgCl to BaCl₂ is 2:1. The moles of BaCl₂ are 1/2 × 3.66 × 10⁻³ mol = 1.83 × 10⁻³ mol.

The volume of 1.50 M barium chloride containing 1.83 × 10⁻³ moles is:

1.83 × 10⁻³ mol × (1 L/1.50 mol) = 1.22 × 10⁻³ L = 1.22 mL

8 0

2 years ago

The first two steps in the industrial synthesis of nitric acid produce nitrogen dioxide from ammonia: 2N0(g) +02(g) 2NO2 (g) The

Tresset [83]

The question is incomplete, complete question is :

The first two steps in the industrial synthesis of nitric acid produce nitrogen dioxide from ammonia:

Step 1 : $4NH_3(g)+5O_2(g)\rightleftharpoons 4NO(g)+6H_2O(g)$

Step 2 : $2NO(g) +O_2(g) \rightleftharpoons 2NO_2 (g)$

The net reaction is:

$4NH_3(g)+7O_2(g)\rightleftharpoons 4NO_2(g)+6H_2O(g)$

Write an equation that gives the overall equilibrium constant K in terms of the equilibrium constants $K_1$ and $K_2$ . If you need to include any physical constants, be sure you use their standard symbols

Answer:

Equation that gives the overall equilibrium constant K in terms of the equilibrium constants $K_1 \& K_2$ :

$K=K_1\time (K_2)^2$

Explanation:

Step 1 : $4NH_3(g)+5O_2(g)\rightleftharpoons 4NO(g)+6H_2O(g)$

Expression of an equilibrium constant can be written as:

$K_1=\frac{[NO]^4[H_2O]^6}{[NH_3]^4[O_2]^5}$

Step 2 : $2NO(g) +O_2(g) \rightleftharpoons 2NO_2 (g)$

Expression of an equilibrium constant can be written as:

$K_2=\frac{[NO_2]^2}{[NO]^2[O_2]}$

The net reaction is:

$4NH_3(g)+7O_2(g)\rightleftharpoons 4NO_2(g)+6H_2O(g)$

Expression of an equilibrium constant can be written as:

$K=\frac{[NO_2]^4[H_2O]^6}{[NH_3]^4[O_2]^7}$

Multiply and divide $[NO]^4$ ;

$K=\frac{[NO_2]^4[H_2O]^6}{[NH_3]^4[O_2]^7}\times \frac{[NO]^4}{[NO]^4}$

$K=\frac{[NO]^4[H_2O]^6}{[NH_3]^4[O_2]^7}\times \frac{[NO_2]^4}{[NO]^4}$

$K=K_1\times \frac{[NO_2]^4}{[O_2]^2[NO]^4}$

$K=K_1\times (\frac{[NO_2]^2}{[O_2]^1[NO]^2})^2$

$K=K_1\time (K_2)^2$

So , the equation that gives the overall equilibrium constant K in terms of the equilibrium constants $K_1 \& K_2$ :

$K=K_1\time (K_2)^2$

4 0

2 years ago

What are the four main parts of the Sun? *

Eddi Din [679]

Answer: The inner layers are core, radiative zone, and convective zone. The putter layers a photosphere, the chromosphere, the transition region and the corona

6 0

2 years ago