Destructive interference in which waves cancel each other out is depicted in region X,Y and Z.
<u>Explanation:</u>
Interface is the particle property of light waves. When incident light beam is made to pass through holes, the waves will combine either constructively or destructively. Constructive interference means the waves having same phase will get added so they will increase in amplitude. While destructive interference means the waves combining have different phases like crests and troughs. So they undergo decrease or complete vanishing of amplitude.
When waves combine in constructive interference, they form bright white light and when they combine in destructive interference, they form dark black light. So the regions X, Y and Z are shown as dark black colors in the diagram, so these regions represent destructive interference in which waves cancel each other out.
Hello Gary!
*Sorry if I'm late*
Your answer is going to be 65.
Element A (which is actually Zinc) has the atomic number of 65. (I remember having got memorize this also).
Pretty much the explanation is that the number of patrons is equivalent to the element's atomic number!
Hope this helps!
Have a nice day :D
<h2>
Explanation:</h2><h3 /><h3>Oxygen- gains 2 electrons to form ions</h3><h3>Fluorine- gains 1 electron to form negative ions</h3><h3>Aluminum - loses three electrons to form ions</h3><h3>Calcium- loses 2 electrons in order to form ions</h3>
<h3>*Non metals gain electrons to form ions</h3><h3>*Metals loses electrons to form ions</h3>
Answer:
The Carbonate (CO2−3) Ion
Unlike O3, though, the actual structure of CO32− is an average of three resonance structures. 2. Carbon has 4 valence electrons, each oxygen has 6 valence electrons, and there are 2 more for the −2 charge. This gives 4 + (3 × 6) + 2 = 24 valence electrons
Explanation:
Balance your chemical reaction first. Start by balancing carbon so you have 2 carbons on both sides.
C2H6 + O2 —> 2CO2 + H2O
Now balance your hydrogen so you have 6 hydrogens on both sides.
C2H6 + O2 —> 2CO2 + 3H2O
Now balance your oxygens. You have 7 oxygens on the right and 2 on the left, so multiply O2 by 3.5.
C2H6 + 3.5O2 —> 2CO2 + 3H2O
However, you can’t have a decimal in a coefficient. So, multiply everything by two.
2C2H6 + 7O2 —> 4CO2 + 6H2O
Now use your mole ratio of 6 mol H2O for every 2 mol of C2H6 to solve.
1.4 mol C2H6 • 6 mol H2O / 2 mol C2H6 = 4.2 mol H2O
D) 4.2 moles
