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xxMikexx [17]
3 years ago
5

Which part of the electromagnetic spectrum has the lowest radiant energy?

Chemistry
2 answers:
Oduvanchick [21]3 years ago
6 0
The answer is D because the lowest frequency has of any type of EM radiation
Veronika [31]3 years ago
5 0
B). Visible Light. Hope that helps

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Of the elements: b, c, f, li, and na. the element with the highest ionization energy is
padilas [110]
Carbon has the highest ionization energy as its energy 1086KJ\Mol and the rest are between 500 and 800. 
6 0
3 years ago
What else is produced during the combustion of butane, C4H10?<br><br> 2C4H10 + 13O2 → <br> + 10H2O
Neko [114]
<h3>Answer:</h3>

8CO₂

<h3>Explanation:</h3>

We are given;

  • Butane, C₄H₁₀
  • Butane is a hydrocarbon in the homologous series known as alkane.

We are required to determine the other product produced in the combustion of butane apart from water.

  • We know that the complete combustion of alkane yields carbon dioxide and water.
  • Therefore, combustion of butane will yield carbon dioxide and water.
  • The balanced equation for the complete combustion of butane will be;

       2C₄H₁₀ + 13O₂ →  8CO₂ + 10H₂O

8 0
3 years ago
Read 2 more answers
Consider a neutrally charged atom that has an atomic mass number of 80, which includes 35 neutrons. how many electrons does this
ivanzaharov [21]
Atomic mass number is the number of protons and neutrons. Subtract 80-35=45 is the number of protons. Because the atom is neutrally charged, the number of protons must equal the number of electrons, so there are 45 electrons.
5 0
3 years ago
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Help me please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
gulaghasi [49]
Sunlight. Solar power!!
5 0
3 years ago
A lake has been infected by some type of new algae that is unknown. Every single day the amount of surface area that the algae t
FrozenT [24]

Answer:

It takes 86 days take to cover half of the lake

Explanation:

In the day #1, the amount of the algae is X,

In the day #2 is 2X

In the day #3 is 2*2*X = X*2²

...

In the day #n the amount of the algae is X*2^(n-1)

Assuming X = 1m³. In the day 87, the area infected was:

1m³*2^(87-1)

7.74x10²⁵m³ is the total area of the lake

the half of this amount is 3.87x10²⁵m³

The time transcurred is:

3.87x10²⁵m³ = 1m³*2^(n-1)

Multiplying for 5 in each side:

ln (3.87x10²⁵) = ln (2^(n-1))

58.9175 = n-1 * 0.6931

85 = n-1

86 = n

<h3>It takes 86 days take to cover half of the lake</h3>

4 0
3 years ago
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